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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 2757 Accepted Submission(s): 1612

删边直接匈牙利算法求最大匹配,如果变小,那么说明这个位置符合条件
#include<iostream>
#include<cstdio>
#include<cstring>
#include<string>
#include<cmath>
using namespace std;
int n,m,k,mark[105],mp[105][105],link[105];
struct node
{
int x,y;
}e[105];
bool dfs(int x)
{
for(int i=1;i<=m;i++)
{
if(mp[x][i]&&mark[i]==-1)
{
mark[i]=1;
if(link[i]==-1||dfs(link[i]))
{
link[i]=x;
return true;
}
}
}
return false;
}
int main()
{
int cas=1;
while(scanf("%d%d%d",&n,&m,&k)!=EOF)
{
int cnt=0;
memset(mp,0,sizeof(mp));
for(int i=1;i<=k;i++)
{
scanf("%d%d",&e[i].x,&e[i].y);
mp[e[i].x][e[i].y]=1;
}
int maxx=0;
memset(link,-1,sizeof(link));
for(int i=1;i<=n;i++)
{
memset(mark,-1,sizeof(mark));
if(dfs(i))
maxx++;
}
for(int i=1;i<=k;i++)
{
int ans=0;
mp[e[i].x][e[i].y]=0;
memset(link,-1,sizeof(link));
for(int i=1;i<=n;i++)
{
memset(mark,-1,sizeof(mark));
if(dfs(i))
ans++;
}
mp[e[i].x][e[i].y]=1;
if(ans<maxx)
cnt++;
}
printf("Board %d have %d important blanks for %d chessmen.\n",cas++,cnt,maxx);
}
return 0;
}
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原文地址:http://www.cnblogs.com/water-full/p/4459691.html