java 对象转JSON 属性为空

标签：

Java 对象转JSON 属性为空，请检查 类中属性是否带有标准的GET和SET方法

for example:

public class example  implements Serializable {
public String entityName;

public String dataSourceName;
 
public String entityVarName;

public String pcChName;

public String pcName;

public List<DBColumn> columns;

}

JSONObject obj  = JSONObject.formObject(example);//obj为空

经过检查发现example 中没有添加get 和set 方法

修改后的example:

public class example implements Serializable {
public String entityName;

public String dataSourceName;

public String entityVarName;

public String pcChName;

public String pcName;

public List<DBColumn> columns;


public String getEntityName() {
return entityName;
}


public void setEntityName(String entityName) {
this.entityName = entityName;
}


public String getDataSourceName() {
return dataSourceName;
}


public void setDataSourceName(String dataSourceName) {
this.dataSourceName = dataSourceName;
}


public String getEntityVarName() {
return entityVarName;
}


public void setEntityVarName(String entityVarName) {
this.entityVarName = entityVarName;
}


public String getPcChName() {
return pcChName;
}


public void setPcChName(String pcChName) {
this.pcChName = pcChName;
}


public String getPcName() {
return pcName;
}


public void setPcName(String pcName) {
this.pcName = pcName;
}


public List<DBColumn> getColumns() {
return columns;
}


public void setColumns(List<DBColumn> columns) {
this.columns = columns;
}
}

java 对象转JSON 属性为空

标签：

原文地址：http://blog.csdn.net/mrzhang0419/article/details/45313077