SQL 仓库管理练习题

create table house (
house_id varchar(10),
city varchar(10),
area  int
)
insert into house values (‘wh1‘,‘北京‘,370);
insert into house values (‘wh2‘,‘上海‘,500);
insert into house values (‘wh3‘,‘广州‘,200);
insert into house values (‘wh4‘,‘武汉‘,400);
create table employee (
house_id varchar(10),
employee_id varchar(10),
salary int
)
insert into employee values (‘wh2‘,‘e1‘,1220);
insert into employee values(‘wh1‘,‘e3‘,1210);
insert into employee values (‘wh2‘,‘e4‘,1250);
insert into employee values (‘wh3‘,‘e6‘,1230);
insert into employee values (‘wh1‘,‘e7‘,1250);
create table purchase (
employee_id varchar(10),
provider_id varchar(10),
purchase_id varchar(10),
purchase_date datetime
)
insert into purchase values (‘e3‘,‘s7‘,‘or67‘,‘2001-6-23‘);
insert into purchase values (‘e1‘,‘s4‘,‘or73‘,‘2001-7-28‘);
insert into purchase values (‘e7‘,‘s4‘,‘or76‘,‘2001-5-25‘) ;
insert into purchase values (‘e6‘,null,‘or77‘,null);
insert into purchase values (‘e3‘,‘s4‘,‘or79‘,‘2001-6-13‘);
insert into purchase values (‘e1‘,null,‘or80‘,null);
insert into purchase values (‘e3‘,null,‘or90‘,null);
insert into purchase values (‘e3‘,‘s3‘,‘or91‘,‘2001-7-13‘);
create table provider(
provider_id varchar(10),
provider_name varchar(max),
[address] varchar(10)
)
insert into provider values (‘s3‘,‘振华电子厂‘,‘西安‘);
insert into provider values (‘s4‘,‘华通电子公司‘,‘北京‘);
insert into provider values (‘s6‘,‘607厂‘,‘郑州‘);
insert into provider values (‘s7‘,‘爱华电子厂‘,‘北京‘);
truncate table provider
--1.从职工关系中检索所有工资值。
select salary from employee;
--2.检索仓库关系中的所有记录
select * from house ;
--3.检索工资多于1230元的职工号
select employee_id from employee where salary>1230;
--4.检索哪些仓库有工资多于1210元的职工。
select distinct house_id from employee where salary>1210;
--5.给出在仓库“wh1”或“wh2”工作，并且工资少于1250元的职工号。
select employee_id from employee where house_id in(‘wh1‘,‘wh2‘) and salary<1250;
--6.找出工资多于1230元的职工号和他们所在的城市。
select employee_id,city from employee e ,house h where e.house_id  = h.house_id and salary>1230;
--7.找出工作在面积大于400的仓库的职工号以及这些职工工作所在的城市。
select employee_id,city from  employee e join house h on e.house_id=h.house_id  and area>400;  
--8 .哪些城市至少有一个仓库的职工工资为1250元。
select city from house  where house_id in (select house_id from employee where salary=1250);
--9.查询所有职工的工资都多于1210元的仓库的信息。
select * from house where house_id in (select house_id from employee where salary>1210);
select * from house where house_id in (select house_id from employee e1 where 1210 < all(select salary from employee e2 where e1.house_id=e2.house_id  ))
--10.找出和职工e4挣同样工资的所有职工。
select * from employee where salary = (select salary from employee where employee_id = ‘e4‘)and employee_id != ‘e4‘;
--11.检索出工资在1220元到1240元范围内的职工信息。
select * from employee where salary between 1220 and 1240;
--12.从供应商关系中检索出全部公司的信息，不要工厂或其他供应商的信息。
select * from provider 
--13.找出不在北京的全部供应商信息。
select * from provider where address !=‘北京‘
--14.按职工的工资值升序检索出全部职工信息。
select * from employee order by salary ;
--15.先按仓库号排序，再按工资排序并输出全部职工信息。
select * from employee order by house_id ,salary ;
--16.找出供应商所在地的数目。
select COUNT(*),address from provider group by address;
--17.求支付的工资总数
select SUM(salary) from employee;
--18.求北京和上海的仓库职工的工资总和 
select SUM(salary) from employee where house_id in (select house_id from house where city in (‘北京‘,‘上海‘))
--19.求所有职工的工资都多于1210元的仓库的平均面积
select AVG(area) from house where house_id in( select house_id from employee e1 where 1210 < all(select salary from employee e2 where e1.house_id=e2.house_id ));
--20.求在wh2仓库工作的职工的最高工资值
select MAX(salary ) from employee where house_id=‘wh2‘;
--21.求每个仓库的职工的平均工资
select AVG(salary ),house_id   from employee group by house_id  
--22.求至少有两个职工的每个仓库的平均工资。
select AVG(salary),house_id from employee group by house_id having COUNT(house_id)>1
--23.找出尚未确定供应商的订购单
select purchase_id from purchase where provider_id is null
--24.列出已经确定了供应商的订购单信息
select * from purchase where provider_id is not null;
--25.查询供应商名
select provider_name from provider 
--26.在订购单表中加入一个新字段总金额，说明完成该订购单所应付出的总金额数。
alter table purchase add sum_money varchar(max);
--27.列出每个职工经手的具有最高总金额的订购单信息。
select * from purchase where sum_money in (select MAX(sum_money) from purchase  group by employee_id)
--28.检索哪些仓库中还没有职工的仓库的信息
select * from house where house_id not in (select house_id from employee )
--29.检索哪些仓库中至少已经有一个职工的仓库的信息
select* from house where house_id in (select house_id from employee )
--30.检索有职工的工资大于或等于wh1仓库中任何一名职工工资的仓库号
select *, house_id from employee where salary >=any (select salary from employee where house_id=‘wh1‘) and house_id!=‘wh1‘
--31.检索有职工的工资大于或等于wh1仓库中所有职工工资的仓库号。
select *,house_id from employee where salary >=all (select salary from employee where house_id=‘wh1‘) and house_id!=‘wh1‘