There are many parallel lines on the ground with the distance of D between each adjacent two. Now, throwing a needle randomly on the ground，please calculate the possibility of that the needle can be across one of the lines.
There are many parallel lines on the ground with the distance of D between each adjacent two. Now, throwing a needle randomly on the ground，please calculate the possibility of that the needle can be across one of the lines.
The input consists of multiple test cases. Each test case contains 2 integers D, L on a single line (1 <= D, L <= 100). The input is ended with EOF.
For each test case, print an integer of (int)(P*10000) where P is the possibility asked above. For example, when P = 0.25658，you should output 2565.
4 2
2 4
3183
8372
#include <iostream>
#include <stdio.h>
#include <string.h>
#include <stack>
#include <queue>
#include <map>
#include <set>
#include <vector>
#include <math.h>
#include <algorithm>
using namespace std;
#define ls 2*i
#define rs 2*i+1
#define up(i,x,y) for(i=x;i<=y;i++)
#define down(i,x,y) for(i=x;i>=y;i--)
#define mem(a,x) memset(a,x,sizeof(a))
#define w(a) while(a)
#define LL long long
const double PI = acos(-1.0);
#define Len 200005
#define mod 19999997
const int INF = 0x3f3f3f3f;
#define exp 1e-8
int main()
{
double L,D;
double P;
w(~scanf("%lf%lf",&D,&L))
{
if(L<D) P=2*L/(PI*D);
else P=1+(2.0/PI)*((L*1.0/D)*(1-sqrt((1-(D*D)/(L*L))))-asin(D*1.0/L));
P=P*10000;
printf("%d\n",(int)P);
}
return 0;
}
CSU1602: Needle Throwing Game(投针问题)
原文地址：http://blog.csdn.net/libin56842/article/details/45460843
