public class Solution {
public String longestCommonPrefix(String[] strs) {
if(strs.length==0)return "";
char[] str=strs[0].toCharArray();
int Min=str.length;
for(int i=1;i<strs.length;i++){
char[] s=strs[i].toCharArray();
int j=0;
while(j<Min && j<s.length && s[j]==str[j])j++;
Min = Min>j?j:Min;
}
return strs[0].substring(0,Min);
}
}char* longestCommonPrefix(char** strs, int strsSize) {
char* str=strs[0];
int i,j;
if(strsSize==0)return "";
for(i=1;i<strsSize;i++){
j=0;
while(str[j] && strs[i][j] && str[j]==strs[i][j])j++;
str[j]=0;
}
return str;
}class Solution {
public:
string longestCommonPrefix(vector<string>& strs) {
if(strs.size()==0)return "";
char* str=(char*)malloc(sizeof(char)*(strs[0].size()+1));
for(int i=0;i<strs[0].size();i++){
str[i]=strs[0][i];
}
str[strs[0].size()]=0;
for(int i=1;i<strs.size();i++){
int j=0;
while(str[j] && strs[i][j] && str[j]==strs[i][j])j++;
str[j]=0;
}
return string(str);
}
};class Solution:
# @param {string[]} strs
# @return {string}
def longestCommonPrefix(self, strs):
if len(strs)==0:return ""
str=strs[0]
Min=len(str)
for i in range(1,len(strs)):
j=0;p=strs[i]
while j<Min and j<len(p) and p[j]==str[j]:j+=1
Min = Min if Min<j else j
return str[:Min]LeetCode 14 Longest Common Prefix (C,C++,Java,Python)
原文地址:http://blog.csdn.net/runningtortoises/article/details/45583695