linux平台学x86汇编（十八）：内联汇编

标签：汇编   内联汇编   inline   

        asm("movl $1, %eax\n\t"
                "movl $0,%ebx\n\t"
                "int $0x80");

#include <stdio.h>
int     result = 10;
int main(int argc, const char *argv[])
{
    asm("addl $1, result\n\t"
        "subl $2, result\n\t");
    printf("the result is  %d\n", result);
    return 0;
}

 .file "inline-as.c"
.globl result
.data
.align 4
.type result, @object
.size result, 4
result:
.long 10
.section .rodata
.LC0:
.string "the result is  %d\n"
.text
.globl main
.type main, @function
main:
pushl %ebp
movl %esp, %ebp
andl $-16, %esp
subl $16, %esp
#APP
# 7 "inline-as.c" 1
addl $1, result
subl $2, result

# 0 "" 2
#NO_APP
movl result, %edx
movl $.LC0, %eax
movl %edx, 4(%esp)
movl %eax, (%esp)
call printf
movl $0, %eax
leave
ret
.size main, .-main
.ident "GCC: (GNU) 4.4.7 20120313 (Red Hat 4.4.7-3)"
.section .note.GNU-stack,"",@progbits

$ ./inline-as
the result is  9
$

    __asm__("addl $1, result\n\t"
        "subl $2, result\n\t");

<span style="font-family:Microsoft YaHei;">asm ("as code": output location : input operands : changed registers);</span>

    #define CAL ({
            asm("addl $1, result\n\t"
            "subl $2, result\n\t");
            })

#include <stdio.h>
#define CAL ({     asm("addl $1, result\n\t"        "subl $2, result\n\t");        })
int     result = 10;
int main(int argc, const char *argv[])
{
    CAL;
    printf("the result is  %d\n", result);
    return 0;
}

linux平台学x86汇编（十八）：内联汇编

标签：汇编   内联汇编   inline   

原文地址：http://blog.csdn.net/shallnet/article/details/45651081