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https://leetcode.com/problems/valid-number/
Validate if a given string is numeric.
Some examples:"0" => true" 0.1 " => true"abc" => false"1 a" => false"2e10" => true
Note: It is intended for the problem statement to be ambiguous. You should gather all requirements up front before implementing one.
正则技术哪家强
1 /** 2 * @param {string} s 3 * @return {boolean} 4 */ 5 var isNumber = function(s) { 6 s = s.trim(); 7 if(s !== "" && /^[-+]?(\d+\.?|\.\d+)\d*([e|E][-+]?\d+)?$/.test(s)){ 8 return true; 9 } 10 return false; 11 };
一开始没想清楚，每多一种情况就加一个else，写的乱七八糟，后来发现都可以合并。
1 /* 2 s = s.trim(); 3 if(s === ""){ 4 return false; 5 }else if(/^[-+]?[e|E]/.test(s)){ 6 return false; 7 }else if(/^[-+]?0$/.test(s)){ 8 return true; 9 }else if(/^[-+]?[0-9]*$/.test(s)){ 10 return true; 11 }else if(/^[-+]?[0-9]+\.[0-9]*$/.test(s)){ 12 return true; 13 }else if(/^[-+]?[0-9]*\.[0-9]+$/.test(s)){ 14 return true; 15 }else if(/^[-+]?[0-9]*[e|E][-+]?[0-9]+$/.test(s)){ 16 return true; 17 }else if(/^[-+]?([0-9]+\.[0-9]*)[e|E][-+]?[0-9]+$/.test(s)){ 18 return true; 19 }else if(/^[-+]?([0-9]*\.[0-9]+)[e|E][-+]?[0-9]+$/.test(s)){ 20 return true; 21 } 22 return false; 23 */
[LeetCode][JavaScript]Valid Number
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原文地址：http://www.cnblogs.com/Liok3187/p/4508019.html
