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Java for LeetCode 108 Convert Sorted Array to Binary Search Tree

时间:2015-05-23 19:58:52      阅读:146      评论:0      收藏:0      [点我收藏+]

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Given an array where elements are sorted in ascending order, convert it to a height balanced BST.

解题思路:

首先要理解,什么叫做height balanced BST Java for LeetCode 110 Balanced Binary Tree,然后就十分容易了,JAVA实现如下:

	public TreeNode sortedArrayToBST(int[] nums) {
		return sortedArrayToBST(nums, 0, nums.length - 1);
	}
	static public TreeNode sortedArrayToBST(int[] nums, int begin, int end) {
		if (begin>end)
			return null;
		TreeNode root = new TreeNode(nums[(begin+end) / 2]);
		root.left=sortedArrayToBST(nums,begin,(begin+end) / 2-1);
		root.right=sortedArrayToBST(nums,(begin+end) / 2+1,end);
		return root;
	}

 

Java for LeetCode 108 Convert Sorted Array to Binary Search Tree

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原文地址:http://www.cnblogs.com/tonyluis/p/4524790.html

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