Java for LeetCode 112 Path Sum

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Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.

For example:
Given the below binary tree and sum = 22,

              5
             /             4   8
           /   /           11  13  4
         /  \              7    2      1

return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.

解题思路：

递归，JAVA实现如下：

    public boolean hasPathSum(TreeNode root, int sum) {
        if(root==null)
        	return false;
    	if(root.val==sum&&root.left==null&&root.right==null)
        	return true;
        else return hasPathSum(root.left,sum-root.val)||hasPathSum(root.right,sum-root.val);
    }

Java for LeetCode 112 Path Sum

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原文地址：http://www.cnblogs.com/tonyluis/p/4524816.html