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#include <stdio.h> #include <iostream> #include <string.h> #include <algorithm> using namespace std; struct stu { char test[25]; int numm; int right[10]; int total; }student[1001]; int cmp(stu a,stu b) { if(a.total != b.total) return a.total>b.total; else return strcmp(a.test,b.test) < 0; //a.test<b.test strcmp返回负数 //return a.test<b.test; 写成这样就WA了 虽然答案是对的 } int main() { int i=0,t,k=0,j=0,m=0,n=0,a,b,A,B,x,y,sum,flag,M,N,G; int count,max=0,ans; char v[1005],p[1005]; int score_per[15]; while(~scanf("%d",&N),N) { scanf("%d%d",&M,&G); memset(score_per,0,sizeof(score_per)); for(i=1;i<=M;i++) scanf("%d",&score_per[i]); for(i=0,t=0;i<N;i++) { student[i].total=0; scanf("%s%d",&student[i].test,&student[i].numm); for (j=0;j<student[i].numm;j++) { scanf("%d",&student[i].right[j]); } for (j=0;j<student[i].numm;j++) { student[i].total += score_per[student[i].right[j]]; } if(G <= student[i].total) t++; memset(student[i].right,0,sizeof(student[i].right)); } sort(student,student+N,cmp); printf("%d\n",t); for (i=0;i<t;i++) { printf("%s %d\n",student[i].test,student[i].total); } } return 0; }
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分析:此题没什么难度,就是主意小细节就好了。
4 5 25 10 10 12 13 15 CS004 3 5 1 3 CS003 5 2 4 1 3 5 CS002 2 1 2 CS001 3 2 3 5 1 2 40 10 30 CS001 1 2 2 3 20 10 10 10 CS000000000000000001 0 CS000000000000000002 2 1 2 0
3 CS003 60 CS001 37 CS004 37 0 1 CS000000000000000002 20HintHuge input, scanf is recommended.
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原文地址:http://blog.csdn.net/xinwen1995/article/details/45971329