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数据结构之---C语言实现串的块链存储表示

时间:2015-05-26 10:48:01      阅读:244      评论:0      收藏:0      [点我收藏+]

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//c语言实现串的块链存储表示
//杨鑫
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define CHUNKSIZE 80
#define TRUE 1  
#define FALSE 0  
#define OK 1  
#define ERROR 0  
#define INFEASIBLE -1  
#define OVERFLOW -2  
char blank='#';
typedef int Status; 
//定义块链存储的串的每个节点
typedef struct Chunk
{
		char ch[CHUNKSIZE];
		struct Chunk *next;
}Chunk;

//定义块链存储的串
typedef struct
{
	Chunk *head, *tail;				
	int curlen;						
}LString;

 void InitString(LString *T)
 { 
   (*T).curlen=0;
   (*T).head=NULL;
   (*T).tail=NULL;
 }

 Status StrAssign(LString *T,char *chars)
 { 
   int i,j,k,l;
   Chunk *p,*q;
   i=strlen(chars); 
   if(!i||strchr(chars,blank))
     return ERROR;
   (*T).curlen=i;
   j=i/CHUNKSIZE; 
   if(i%CHUNKSIZE)
     j++;
   for(k=0;k<j;k++)
   {
     p=(Chunk*)malloc(sizeof(Chunk));
     if(!p)
       return ERROR;
     if(k==0) 
       (*T).head=q=p;
     else
     {
       q->next=p;
       q=p;
     }
     for(l=0;l<CHUNKSIZE&&*chars;l++)
       *(q->ch+l)=*chars++;
     if(!*chars) 
     {
       (*T).tail=q;
       q->next=NULL;
       for(;l<CHUNKSIZE;l++) 
         *(q->ch+l)=blank;
     }
   }
   return OK;
 }

 Status StrCopy(LString *T,LString S)
 { 
   Chunk *h=S.head,*p,*q;
   (*T).curlen=S.curlen;
   if(h)
   {
     p=(*T).head=(Chunk*)malloc(sizeof(Chunk));
     *p=*h; 
     h=h->next;
     while(h)
     {
       q=p;
       p=(Chunk*)malloc(sizeof(Chunk));
       q->next=p;
       *p=*h;
       h=h->next;
     }
     p->next=NULL;
     (*T).tail=p;
     return OK;
   }
   else
    return ERROR;
 }

 Status StrEmpty(LString S)
 {
   if(S.curlen)
     return FALSE;
   else
     return TRUE;
 }

 int StrCompare(LString S,LString T)
 { 
   int i=0;
   Chunk *ps=S.head,*pt=T.head;
   int js=0,jt=0; 
   while(i<S.curlen&&i<T.curlen)
   {
     i++; 
     while(*(ps->ch+js)==blank)
     {
       js++;
       if(js==CHUNKSIZE)
       {
         ps=ps->next;
         js=0;
       }
     }; 
     while(*(pt->ch+jt)==blank)
     {
       jt++;
       if(jt==CHUNKSIZE)
       {
         pt=pt->next;
         jt=0;
       }
     }; 
     if(*(ps->ch+js)!=*(pt->ch+jt))
       return *(ps->ch+js)-*(pt->ch+jt);
     else 
     {
       js++;
       if(js==CHUNKSIZE)
       {
         ps=ps->next;
         js=0;
       }
       jt++;
       if(jt==CHUNKSIZE)
       {
         pt=pt->next;
         jt=0;
       }
     }
   }
   return S.curlen-T.curlen;
 }

 int StrLength(LString S)
 { 
   return S.curlen;
 }

 Status ClearString(LString *S)
 { 
   Chunk *p,*q;
   p=(*S).head;
   while(p)
   {
     q=p->next;
     free(p);
     p=q;
   }
   (*S).head=NULL;
   (*S).tail=NULL;
   (*S).curlen=0;
   return OK;
 }

 Status Concat(LString *T,LString S1,LString S2)
 { 
   LString a1,a2;
   InitString(&a1);
   InitString(&a2);
   StrCopy(&a1,S1);
   StrCopy(&a2,S2);
   (*T).curlen=S1.curlen+S2.curlen;
   (*T).head=a1.head;
   a1.tail->next=a2.head;
   (*T).tail=a2.tail;
   return OK;
 }

 Status SubString(LString *Sub, LString S,int pos,int len)
 { 
   Chunk *p,*q;
   int i,k,n,flag=1;
   if(pos<1||pos>S.curlen||len<0||len>S.curlen-pos+1)
     return ERROR;
   n=len/CHUNKSIZE;
   if(len%CHUNKSIZE)
     n++; 
   p=(Chunk*)malloc(sizeof(Chunk));
   (*Sub).head=p;
   for(i=1;i<n;i++)
   {
     q=(Chunk*)malloc(sizeof(Chunk));
     p->next=q;
     p=q;
   }
   p->next=NULL;
   (*Sub).tail=p;
   (*Sub).curlen=len;
   for(i=len%CHUNKSIZE;i<CHUNKSIZE;i++)
     *(p->ch+i)=blank;
   q=(*Sub).head; 
   i=0; 
   p=S.head; 
   n=0; 
   while(flag)
   {
     for(k=0;k<CHUNKSIZE;k++)
       if(*(p->ch+k)!=blank)
       {
         n++;
         if(n>=pos&&n<=pos+len-1)
         {
           if(i==CHUNKSIZE)
           { 
             q=q->next;
             i=0;
           }
           *(q->ch+i)=*(p->ch+k);
           i++;
           if(n==pos+len-1)
           {
             flag=0;
             break;
           }
         }
       }
     p=p->next;
   }
   return OK;
 }

 int Index(LString S,LString T,int pos)
 {
   int i,n,m;
   LString sub;
   if(pos>=1&&pos<=StrLength(S))
   {
     n=StrLength(S); 
     m=StrLength(T); 
     i=pos;
     while(i<=n-m+1)
     {
       SubString(&sub,S,i,m); 
       if(StrCompare(sub,T)!=0) 
         ++i;
       else
         return i;
     }
   }
   return 0;
 }

 void Zip(LString *S)
 { 
   int j,n=0;
   Chunk *h=(*S).head;
   char *q;
   q=(char*)malloc(((*S).curlen+1)*sizeof(char));
   while(h) 
   {
     for(j=0;j<CHUNKSIZE;j++)
       if(*(h->ch+j)!=blank)
       {
         *(q+n)=*(h->ch+j);
         n++;
       }
     h=h->next;
   }
   *(q+n)=0;
   ClearString(S); 
   StrAssign(S,q);
 }

 Status StrInsert(LString *S,int pos,LString T)
 {
   int i,j,k;
   Chunk *p,*q;
   LString t;
   if(pos<1||pos>StrLength(*S)+1)
     return ERROR;
   StrCopy(&t,T); 
   Zip(S); 
   i=(pos-1)/CHUNKSIZE; 
   j=(pos-1)%CHUNKSIZE;
   p=(*S).head;
   if(pos==1)
   {
     t.tail->next=(*S).head;
     (*S).head=t.head;
   }
   else if(j==0) 
   {
     for(k=1;k<i;k++)
       p=p->next;
     q=p->next; 
     p->next=t.head; 
     t.tail->next=q;
     if(q==NULL) 
       (*S).tail=t.tail; 
   }
   else 
   {
     for(k=1;k<=i;k++)
       p=p->next; 
     q=(Chunk*)malloc(sizeof(Chunk)); 
     for(i=0;i<j;i++)
       *(q->ch+i)=blank; 
     for(i=j;i<CHUNKSIZE;i++)
     {
       *(q->ch+i)=*(p->ch+i);
       *(p->ch+i)=blank;
     }
     q->next=p->next;
     p->next=t.head;
     t.tail->next=q;
   }
   (*S).curlen+=t.curlen;
   Zip(S);
   return OK;
 }

 Status StrDelete(LString *S,int pos,int len)
 { 
   int i=1; 
   Chunk *p=(*S).head;
   int j=0;
   if(pos<1||pos>(*S).curlen-len+1||len<0) 
     return ERROR;
   while(i<pos)
   {
     while(*(p->ch+j)==blank)
     {
       j++;
       if(j==CHUNKSIZE) 
       {
         p=p->next;
         j=0;
       }
     }
     i++;
     j++;
     if(j==CHUNKSIZE)
     {
       p=p->next;
       j=0;
     }
   }; 
   while(i<pos+len)
   {
     while(*(p->ch+j)==blank)
     {
       j++;
       if(j==CHUNKSIZE) 
       {
         p=p->next;
         j=0;
       }
     }
     *(p->ch+j)=blank; 
     i++;
     j++;
     if(j==CHUNKSIZE)
     {
       p=p->next;
       j=0;
     }
   };
   (*S).curlen-=len;
   return OK;
 }

 Status Replace(LString *S,LString T,LString V)
 { 
   int i=1; 
   if(StrEmpty(T)) 
     return ERROR;
   do
   {
     i=Index(*S,T,i); 
     if(i) 
     {
       StrDelete(S,i,StrLength(T));
       StrInsert(S,i,V);
       i+=StrLength(V); 
     }
   }while(i);
   return OK;
 }

 void StrPrint(LString T)
 {
   int i=0,j;
   Chunk *h;
   h=T.head;
   while(i<T.curlen)
   {
     for(j=0;j<CHUNKSIZE;j++)
       if(*(h->ch+j)!=blank) 
       {
         printf("%c",*(h->ch+j));
         i++;
       }
     h=h->next;
   }
   printf("\n");
 }

 void DestroyString()
 {
 }


 int main()
 {
   char *s1="ABCDEFGHI", *s2="12345", *s3="", *s4="asd#tr", *s5="ABCD";
   Status k;
   int pos,len;
   LString t1,t2,t3,t4;
   InitString(&t1);
   InitString(&t2);
   printf("===============分隔符=========================\n");
   printf("初始化串t1后,串t1空否?%d(1:空 0:否) 串长=%d\n",StrEmpty(t1),StrLength(t1));
   k=StrAssign(&t1,s3);
   if(k==OK)
   {
     printf("串t1为: \n");
     StrPrint(t1);
   }
   else
     printf("出错\n");
   k=StrAssign(&t1,s4);
   if(k==OK)
   {
     printf("串t1为: \n");
     StrPrint(t1);
   }
   else
     printf("出错\n");
   k=StrAssign(&t1,s1);
   if(k==OK)
   {
     printf("串t1为: \n");
     StrPrint(t1);
   }
   else
     printf("出错\n");
   printf("串t1空否?%d(1:空 0:否) 串长=%d\n",StrEmpty(t1),StrLength(t1));
   StrAssign(&t2,s2);
   printf("串t2为: \n");
   StrPrint(t2);
   StrCopy(&t3,t1);
   printf("由串t1拷贝得到串t3,串t3为: \n");
   StrPrint(t3);
   InitString(&t4);
   StrAssign(&t4,s5);
   printf("串t4为: ");
   StrPrint(t4);
   Replace(&t3,t4,t2);
   printf("===============分隔符=========================\n");
   printf("用t2取代串t3中的t4串后,串t3为: \n");
   StrPrint(t3);
   ClearString(&t1);
   printf("===============分隔符=========================\n");
   printf("清空串t1后,串t1空否?%d(1:空 0:否) 串长=%d\n",StrEmpty(t1),StrLength(t1));
   Concat(&t1,t2,t3);
   printf("===============分隔符=========================\n");
   printf("串t1(=t2+t3)为: \n");
   StrPrint(t1);
   Zip(&t1);
   printf("去除不必要的占位符后,串t1为: \n");
   StrPrint(t1);
   pos=Index(t1,t3,1);
   printf("pos=%d\n",pos);
   printf("===============分隔符=========================\n");
   printf("在串t1的第pos个字符之前插入串t2,请输入pos: \n");
   scanf("%d",&pos);
   k=StrInsert(&t1,pos,t2);
   if(k)
   {
     printf("插入串t2后,串t1为: \n");
     StrPrint(t1);
   }
   else
     printf("插入失败!\n");
   return 0;
 }


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数据结构之---C语言实现串的块链存储表示

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原文地址:http://blog.csdn.net/u012965373/article/details/46003857

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