Description
Input
Output
Sample Input
30 25 27 30 34 39 45 52 60 69 79 69 60 52 45 39 34 30 26 22 18 82 78 74 70 66 67 64 60 65 80 0
Sample Output
5
Hint
Source
题意:有N(1 <= N <=20000)个音符的序列来表示一首乐曲,每个音符都是1..88范围内的整数,现在要找一个重复的主题。“主题”是整个音符序列的一个子串,它需要满足如下条件:
#include <iostream> #include <stdio.h> #include <string.h> #include <stack> #include <queue> #include <map> #include <set> #include <vector> #include <math.h> #include <bitset> #include <algorithm> #include <climits> using namespace std; #define LS 2*i #define RS 2*i+1 #define UP(i,x,y) for(i=x;i<=y;i++) #define DOWN(i,x,y) for(i=x;i>=y;i--) #define MEM(a,x) memset(a,x,sizeof(a)) #define W(a) while(a) #define gcd(a,b) __gcd(a,b) #define LL long long #define N 20005 #define MOD 1000000007 #define INF 0x3f3f3f3f #define EXP 1e-8 int wa[N],wb[N],wsf[N],wv[N],sa[N]; int rank[N],height[N],s[N],a[N],n; char str1[N],str2[N]; //sa:字典序中排第i位的起始位置在str中第sa[i] //rank:就是str第i个位置的后缀是在字典序排第几 //height:字典序排i和i-1的后缀的最长公共前缀 int cmp(int *r,int a,int b,int k) { return r[a]==r[b]&&r[a+k]==r[b+k]; } void getsa(int *r,int *sa,int n,int m)//n要包含末尾添加的0 { int i,j,p,*x=wa,*y=wb,*t; for(i=0; i<m; i++) wsf[i]=0; for(i=0; i<n; i++) wsf[x[i]=r[i]]++; for(i=1; i<m; i++) wsf[i]+=wsf[i-1]; for(i=n-1; i>=0; i--) sa[--wsf[x[i]]]=i; p=1; j=1; for(; p<n; j*=2,m=p) { for(p=0,i=n-j; i<n; i++) y[p++]=i; for(i=0; i<n; i++) if(sa[i]>=j) y[p++]=sa[i]-j; for(i=0; i<n; i++) wv[i]=x[y[i]]; for(i=0; i<m; i++) wsf[i]=0; for(i=0; i<n; i++) wsf[wv[i]]++; for(i=1; i<m; i++) wsf[i]+=wsf[i-1]; for(i=n-1; i>=0; i--) sa[--wsf[wv[i]]]=y[i]; t=x; x=y; y=t; x[sa[0]]=0; for(p=1,i=1; i<n; i++) x[sa[i]]=cmp(y,sa[i-1],sa[i],j)? p-1:p++; } } void getheight(int *r,int n)//n不保存最后的0 { int i,j,k=0; for(i=1; i<=n; i++) rank[sa[i]]=i; for(i=0; i<n; i++) { if(k) k--; else k=0; j=sa[rank[i]-1]; while(r[i+k]==r[j+k]) k++; height[rank[i]]=k; } } int ans; int fun(int k) { int i,maxn,minn; maxn = minn = sa[1]; UP(i,2,n) { if(height[i]>=k && i<n) { minn = min(minn,sa[i]); maxn = max(maxn,sa[i]); continue; } if(maxn-minn>=k) return 1; maxn = minn = sa[i]; } return 0; } int main() { int i,j,k; W((~scanf("%d",&n),n)) { UP(i,0,n-1) { scanf("%d",&s[i]); } UP(i,0,n-2) { s[i] = s[i+1]-s[i]+100; } s[--n] = 0; getsa(s,sa,n+1,200); getheight(s,n); int l = 4,r = n; W(l<=r) { int mid = (l+r)/2; if(fun(mid)) { ans = mid; l=mid+1; } else r = mid-1; } ans++; printf("%d\n",ans<5?0:ans); } return 0; }
原文地址:http://blog.csdn.net/libin56842/article/details/46233687