oracle判断一个字符串中是否包含另外一个字符串

create or replace function checks(v_a varchar2,v_b varchar)
  return number
  as
     num number;
     cou number;
  begin
     num := -1;
     cou:=0;
     for i in 1..length(v_b) loop
        if instr(v_a,substr(v_b,i,1))>0 then
     cou:=cou+1;
        end if;
     end loop;
     if cou=length(v_b) then
     return cou;
     end if;
     dbms_output.put_line(cou||‘    ‘||length(v_b));
  return num;
  end;
 
结果：
 SQL> select * from a;
 
A          B
 ---------- ----------
 asdf       sd
 asdf       ad
 asdf       df
 asdf       asdf
 
SQL> select * from a where checks(a,b)>0;
 
A          B
 ---------- ----------
 asdf       sd
 asdf       ad
 asdf       df
 asdf       asdf