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建表:
create table STU ( id NUMBER(3), name VARCHAR2(10) )
create table EXAM ( eid INTEGER not null, stuid INTEGER not null, coursename VARCHAR2(20) not null, score FLOAT )
insert into stu (ID, NAME) values (3, ‘kity‘); insert into stu (ID, NAME) values (2, ‘tom‘); insert into stu (ID, NAME) values (1, ‘jack‘); insert into stu (ID, NAME) values (4, ‘nono‘); insert into exam (ID, GRADE) values (11, 89); insert into exam (ID, GRADE) values (2, 76); insert into exam (ID, GRADE) values (1, 56);
select stu.id, exam.id, stu.name, exam.grade from stu left join exam on stu.id = exam.id; --左连接 select stu.id, exam.id, stu.name, exam.grade from stu,exam where stu.id = exam.id(+); --左链接 select stu.id, exam.id, stu.name, exam.grade from stu,exam where stu.id(+) = exam.id; --右链接
select stu.id, exam.id, stu.name, exam.grade from stu,exam where stu.id = exam.id(+); --左链接 -- "+" 号在右侧,则就是左连接,查询出来的结果集就以stu的总结果数为准,而exam --中如果没有与stu关联上,则以空 补足,具体可以看sql语句的执行结果的截图 select stu.id, exam.id, stu.name, exam.grade from stu,exam where stu.id(+) = exam.id; --右链接 -- "+" 号在左侧,则是右连接,同上。
左连接:
右连接:
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原文地址:http://www.cnblogs.com/Sunnor/p/4550499.html