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JSON.NET 简单的使用

时间:2014-06-18 09:10:55      阅读:184      评论:0      收藏:0      [点我收藏+]

标签:des   android   style   class   blog   code   

JSON.NET(http://json.codeplex.com/)使用来将.NET中的对象转换为JSON字符串(序列化?),或者将JSON字符串转换为.NET中已有类型的对象(反序列化?)

首先为了例子随便定义一个类型:

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public class Product
{
    public string Name { get; set; }
    public DateTime Expiry { get; set; }
    public decimal Price { get; set; }
    public string[] Sizes { get; set; }

    public override string ToString()
    {
        return string.Format("Name:{0},Expiry:{1},Price:{2},SizesCount:{3}"
            , Name, Expiry, Price, Sizes.Length);
    }
}
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初始化对象:

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public static void Main(string[] passwordargs)
{
    Product product = new Product()
    {
        Name = "android",
        Expiry = DateTime.Now,
        Price = 2000,
        Sizes = new string[] { "1.5", "2.2", "4.1" }
    };
}
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进行到JSON的转换:

Console.WriteLine(JsonConvert.SerializeObject(product));

输出结果:

{"Name":"android","Expiry":"2013-08-30T09:50:11.5147845+08:00","Price":2000.0,"Sizes":["1.5","2.2","4.1"]}

其它看起来一切正常,除了这个日期有点怪

格式化日期:

//设置日期时间的格式,与DataTime类型的ToString格式相同
IsoDateTimeConverter iso = new IsoDateTimeConverter();
iso.DateTimeFormat = "yyyy-MM-dd HH:mm:ss";

Console.WriteLine(JsonConvert.SerializeObject(product, iso));

输出结果:

{"Name":"android","Expiry":"2013-08-30 09:53:58","Price":2000.0,"Sizes":["1.5","2.2","4.1"]}

从JSON到对象的转换:

string str = "{\"Name\":\"android\",\"Expiry\":\"2013-08-30 09:53:58\",\"Price\":2000.0,\"Sizes\":[\"1.5\",\"2.2\",\"4.1\"]}";

Product p = (Product)JsonConvert.DeserializeObject(str, typeof(Product));

Console.WriteLine(p.ToString());

输出结果:

Name:android,Expiry:2013/8/30 9:53:58,Price:2000.0,SizesCount:3

从JSON到键值对的转换:

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string strJson = @"{""Name1"": ""小明"",""Name2"": ""小花"",""Name3"": ""小红""}";

Dictionary<string, string> _dictionary = JsonConvert.DeserializeObject<Dictionary<string, string>>(strJson);

foreach (KeyValuePair<string, string> kp in _dictionary)
{
    Console.WriteLine(kp.Key + ":" + kp.Value);
}
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输出结果:

Name1:小明 
Name2:小花 
Name3:小红

从字符串转换到JSON对象,以及JSON对象的简单使用:

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string strJson2 = @"{ ""student"": { ""Name1"": ""小明"" , ""Name2"": ""小花"" , ""Name3"": ""小红""} }";

JObject jsonObj = JObject.Parse(strJson2);

Console.WriteLine(jsonObj["student"]["Name1"].ToString());
Console.WriteLine(jsonObj["student"]["Name2"].ToString());
Console.WriteLine(jsonObj["student"]["Name3"].ToString());
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输出结果:

小明 
小花 
小红

直接生成JSON对象:

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JObject json =
    new JObject(
    new JProperty("Channel",
        new JObject(
        new JProperty("title", "JSON"),
        new JProperty("link", "JSON.NET"),
        new JProperty("description", "JSON.NET Description"),
        new JProperty("items",
            new JArray(
            new JObject(new JProperty("haha1", "123")),
            new JObject(new JProperty("haha2", "456")),
            new JObject(new JProperty("haha3", "789"))
                )))));

Console.WriteLine(json.ToString());
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输出结果:


  "Channel": { 
    "title": "JSON", 
    "link": "JSON.NET", 
    "description": "JSON.NET Description", 
    "items": [ 
      { 
        "haha1": "123" 
      }, 
      { 
        "haha2": "456" 
      }, 
      { 
        "haha3": "789" 
      } 
    ] 
  } 
}

暂时先记录这么多,以后再继续补充

JSON.NET 简单的使用,布布扣,bubuko.com

JSON.NET 简单的使用

标签:des   android   style   class   blog   code   

原文地址:http://www.cnblogs.com/superfeeling/p/3793372.html

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