【问题】
Given n points
on a 2D plane, find the maximum number of points that lie on the same straight line.
【思路】
对每一个点,分别计算这个点和其他所有点构成的斜率,具有相同斜率最多的点所构成的直线,就是具有最多点的直线。
【代码】
class Point: def __init__(self, a=0, b=0): self.x = a self.y = b class Solution: # @param points, a list of Points # @return an integer def maxPoints(self, points): length = len(points) if length < 3: return length res = -1 for i in xrange(length): slope = {'inf': 0} samePointNum = 1 for j in xrange(length): if i == j: continue elif points[i].x == points[j].x and points[i].y != points[j].y: slope['inf'] +=1 elif points[i].x != points[j].x: k = 1.0 * (points[j].y - points[i].y) / (points[j].x - points[i].x) slope[k] = 1 if k not in slope.keys() else slope[k] + 1 else: samePointNum += 1 res = max(res, max(slope.values()) + samePointNum) return res
Max Points on a Line (Python),布布扣,bubuko.com
原文地址:http://blog.csdn.net/jjjcainiao/article/details/33411837