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Given a list of non negative integers, arrange them such that they form the largest number.
For example, given [3, 30, 34, 5, 9]
, the largest formed number is 9534330
.
Note: The result may be very large, so you need to return a string instead of an integer.
解题思路:
先把int数组转为String,然后做一个比较器,这里有一个小技巧可以用 (o2 + o1).compareTo(o1 + o2)作为比较器,可以将"大数字"放到前面,然后按照比较器的顺序输出即可,JAVA实现如下:
public String largestNumber(int[] nums) { String[] str=new String[nums.length]; for(int i=0;i<nums.length;i++) str[i]=String.valueOf(nums[i]); Comparator<String> comp = new Comparator<String>() { public int compare(String o1, String o2) { return (o2 + o1).compareTo(o1 + o2); } }; Arrays.sort(str, comp); if (str[0].equals("0")) return "0"; StringBuilder sb=new StringBuilder(); for (String s : str) sb.append(s); return sb.toString(); }
Java for LeetCode 179 Largest Number
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原文地址:http://www.cnblogs.com/tonyluis/p/4557087.html