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Oracle Flashback Technologies - 闪回查询
查看表中,某行数据的修改记录
#创建一个表,并插入和修改数据
SQL> create table y3(id int,name varchar2(20)); Table created. SQL> insert into y3 values(1,‘wahaha‘); 1 row created. SQL> commit; Commit complete. SQL> update y3 set name=‘nongfushanquan‘ where id=1; 1 row updated. SQL> commit; Commit complete. SQL> update y3 set name=‘kaifei‘ where id=1; 1 row updated. SQL> commit; Commit complete. SQL> update y3 set name=‘pijiu‘ where id=1; 1 row updated. SQL> commit; Commit complete. SQL> update y3 set name=‘hongniu‘ where id=1; 1 row updated. SQL> commit; Commit complete. SQL> update y3 set name=‘kele‘ where id=1; 1 row updated. SQL> commit; Commit complete. SQL>
#查询
#查询 SQL> select 2 name, 3 versions_starttime, 4 versions_startscn, 5 versions_endtime, 6 versions_endscn, 7 versions_xid, 8 versions_operation 9 from y3 10 versions between scn minvalue and maxvalue 11 where id = 1 12 order by 3 13 / NAME VERSIONS_STARTTIME VERSIONS_STARTSCN VERSIONS_ENDTIME VERSIONS_ENDSCN VERSIONS_XID V -------------------- ------------------------- ----------------- ------------------------- --------------- ---------------- - wahaha 23-JUN-15 08.36.07 AM 1466318 23-JUN-15 08.36.46 AM 1466333 0400200065030000 I nongfushanquan 23-JUN-15 08.36.46 AM 1466333 23-JUN-15 08.37.16 AM 1466347 0A00040015040000 U kaifei 23-JUN-15 08.37.16 AM 1466347 23-JUN-15 08.37.31 AM 1466355 070018009D030000 U pijiu 23-JUN-15 08.37.31 AM 1466355 23-JUN-15 08.37.49 AM 1466364 01000D0048030000 U hongniu 23-JUN-15 08.37.49 AM 1466364 23-JUN-15 08.39.04 AM 1466400 02001B0021040000 U kele 23-JUN-15 08.39.04 AM 1466400 06000400DC040000 U 6 rows selected. SQL>
查看语句
select name, versions_starttime, versions_startscn, versions_endtime, versions_endscn, versions_xid, versions_operation from y3 versions between scn minvalue and maxvalue #versions between timestamp minvalue and maxvalue 也可以根据时间戳来查看 where id = 1 order by 3 /
Oracle Flashback Technologies - 闪回查询
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原文地址:http://www.cnblogs.com/abclife/p/4595843.html