标签:
A*初步
A*要保证最短路一定要估价函数小于实际值,越接近越好
/*jerryRey 转载请注明出处,谢谢 http://www.cnblogs.com/jerryRey/ */
#include<cstdio> #include<queue> #include<cstring> #include<algorithm> using namespace std; const int N = 8; bool C[N][N]; struct node { int g,h; int x, y; bool operator < (const node& rhs) const{ if(g + h > rhs.g + rhs.h) return true; if(g + h < rhs.h + rhs.g ) return false; return g > rhs.g; } }; int tax,tay; inline void getH(node& o) { o.h = (abs(o.x-tax)+abs(o.y-tay))>>1; } #define joinC(n) C[n.x][n.y] = true int dx[] = {1,2, 1, 2,-1,-2,-1,-2}; int dy[] = {2,1,-2,-1,-2,-1, 2, 1}; int bfs(node &start) { priority_queue<node> Q; memset(C,false,sizeof(C)); Q.push(start); joinC(start); node cur,nxt; int i,nx,ny; while(Q.size()){ cur = Q.top();Q.pop(); if(cur.x == tax && cur.y == tay) return cur.g; for(i = 0; i < N; i++){ nx = cur.x + dx[i]; ny = cur.y + dy[i]; if(nx >= N || nx < 0 || ny >= N || ny < 0 || C[nx][ny]) continue; nxt.x = nx ; nxt.y = ny; nxt.g = cur.g+1 ; getH(nxt); joinC(nxt); Q.push(nxt); } } return -1; } int main() { node start; char fro[3],to[3]; char ch; int n; while(~scanf("%s",fro)){ scanf("%s",to); sscanf(fro,"%c",&ch); sscanf(fro+1,"%1d",&n); start.x = ch -‘a‘; start.y = n-1; start.g = 0; sscanf(to,"%c",&ch); sscanf(to+1,"%1d",&n); tax = ch - ‘a‘; tay = n-1; getH(start); printf("To get from %s to %s takes %d knight moves.\n",fro,to,bfs(start)); } return 0; }
[bfs][A star][入门题]uva439 knightMoves
标签:
原文地址:http://www.cnblogs.com/jerryRey/p/4597277.html