标签:
1 class Solution { 2 public: 3 /** 4 * @param A: sorted integer array A which has m elements, 5 * but size of A is m+n 6 * @param B: sorted integer array B which has n elements 7 * @return: void 8 */ 9 void mergeSortedArray(int A[], int m, int B[], int n) { 10 // write your code here 11 int pa = m - 1, pb = n - 1, p = m + n - 1; 12 while (pa >= 0 && pb >= 0) { 13 if (A[pa] >= B[pb]) A[p--] = A[pa--]; 14 else A[p--] = B[pb--]; 15 } 16 while (pb >= 0) A[p--] = B[pb--]; 17 } 18 };
标签:
原文地址:http://www.cnblogs.com/jcliBlogger/p/4609088.html