当我们使用Spring时候在Xml文件中通过
<bean id="service" class="com.finance.service.AmountServiceImpl" />
配置就可以操作该Bean的属性和方法,那么Spring到底是如何实现的呢?下面让我们自己实现这个过程。
首先我模拟Spring的命名方式创建一个Bean管理类MyClassPathXMLApplicationContext.java,代码如下:
// 自定义容器
public class MyClassPathXMLApplicationContext {
private List<BeanDefinition> beanDefines = new ArrayList<BeanDefinition>();
private Map<String, Object> singletons = new HashMap<String, Object>();
public MyClassPathXMLApplicationContext(String filename){
// 1、读取配置文件
this.readXML(filename);
// 2、实例化Bean
this.instanceBeans();
}
/**
* 完成bean的实例化
*/
private void instanceBeans() {
for(BeanDefinition beanDefinition : beanDefines){
try {
if(beanDefinition.getClassName()!=null && !"".equals(beanDefinition.getClassName().trim()))
singletons.put(beanDefinition.getId(), Class.forName(beanDefinition.getClassName()).newInstance());
} catch (Exception e) {
e.printStackTrace();
}
}
}
/**
* 读取xml配置文件
* @param filename
*/
private void readXML(String filename) {
SAXReader saxReader = new SAXReader();
Document document=null;
try{
URL xmlpath = this.getClass().getClassLoader().getResource(filename);
document = saxReader.read(xmlpath);
Map<String,String> nsMap = new HashMap<String,String>();
nsMap.put("ns","http://www.springframework.org/schema/beans");//加入命名空间
XPath xsub = document.createXPath("//ns:beans/ns:bean");//创建beans/bean查询路径
xsub.setNamespaceURIs(nsMap);//设置命名空间
List<Element> beans = xsub.selectNodes(document);//获取文档下所有bean节点
for(Element element: beans){
String id = element.attributeValue("id");//获取id属性值
String clazz = element.attributeValue("class"); //获取class属性值
BeanDefinition beanDefine = new BeanDefinition(id, clazz);
beanDefines.add(beanDefine);
}
}catch(Exception e){
e.printStackTrace();
}
}
/**
* 获取bean实例
* @param beanName
* @return
*/
public Object getBean(String beanName){
return this.si呢gletons.get(beanName);
}
}
配置文件如下:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-2.5.xsd">
<bean id="personService" class="cn.itcast.service.impl.PersonServiceBean"></bean>
</beans>
下面我们来测试一下:
public class SpringTest {
@BeforeClass
public static void setUpBeforeClass() throws Exception {
}
@Test public void instanceSpring(){
MyClassPathXMLApplicationContext ctx = new MyClassPathXMLApplicationContext("beans.xml");
PersonService personService = (PersonService)ctx.getBean("personService");
personService.save();
}
}
运行成功
原文地址:http://blog.csdn.net/fuyuwei2015/article/details/46861463