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LeetCode#202 Happy Number

时间:2015-07-17 17:54:55      阅读:111      评论:0      收藏:0      [点我收藏+]

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Problem Definition:

Write an algorithm to determine if a number is "happy".

A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.

Example: 19 is a happy number

  • 12 + 92 = 82
  • 82 + 22 = 68
  • 62 + 82 = 100
  • 12 + 02 + 02 = 1

Solution:

 1 def isHappy(self,n):
 2         d={}             #用字典来存储n
 3         while True:
 4             if n==1:    #一旦某个平方和为1,则肯定happy
 5                 return True
 6             if n not in d:
 7                 d[n]=0  #0只是一个标记
 8                 n=self.getSum(n)
 9             else:         #出现重复且不是1的平方和,不happy
10                 return False
11 def getSum(self,n):
12         s=0
13         while n!=0:
14             a=n%10
15             n=n/10
16             s+=a**2
17         return s

 

LeetCode#202 Happy Number

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原文地址:http://www.cnblogs.com/acetseng/p/4654802.html

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