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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 6062 Accepted Submission(s): 2810
#include<stdio.h>
#include<string.h>
#define mod 10007
#define MAX 200010
char p[MAX];
int f[MAX];
int dp[MAX];
void getfail()
{
int i,j;
f[0]=f[1]=0;
int len=strlen(p);
for(i=1;i<len;i++)
{
j=f[i];
while(j&&p[i]!=p[j])
j=f[j];
f[i+1]=p[i]==p[j]?j+1:0;
}
}
int main()
{
int n,m,j,i,s,t;
scanf("%d",&t);
while(t--)
{
scanf("%d",&n);
scanf("%s",p);
getfail();
s=0;
dp[0]=0;
for(i=1;i<=n;i++)
{
dp[i]=(dp[f[i]]%mod+1)%mod;
s=(s%mod+dp[i]%mod)%mod;
}
printf("%d\n",s);
}
return 0;
}
喝豆浆 3336 Count the string【kmp算法求前缀在原字符串中出现总次数】
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原文地址:http://www.cnblogs.com/tonghao/p/4670877.html