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;CREATE TABLE TabTest ( `id` INT(11) NOT NULL AUTO_INCREMENT ,`factorA` VARCHAR(255) NOT NULL DEFAULT ‘ ‘ ,`factorB` VARCHAR(255) NOT NULL DEFAULT ‘ ‘ ,`factorC` DECIMAL(10,2) NOT NULL DEFAULT 0 ,`remark` VARCHAR(255) NOT NULL DEFAULT ‘ ‘ , PRIMARY KEY (`id`) ) ENGINE=INNODB AUTO_INCREMENT=0 DEFAULT CHARSET=utf8 COMMENT=‘‘; INSERT INTO TabTest(factorA, factorB, factorC, remark) SELECT ‘A1‘, ‘B1‘, 0.5, ‘1..‘ UNION ALL SELECT ‘A1‘, ‘B1‘, 0.5, ‘2..‘ UNION ALL SELECT ‘A2‘, ‘B2‘, 0.5, ‘3..‘ UNION ALL SELECT ‘A2‘, ‘B2‘, 1.5, ‘4..‘ UNION ALL SELECT ‘A2‘, ‘B2‘, 0.5, ‘5..‘ ;SELECT * FROM TabTest;
-- 方案一 ;DELETE FROM TabTest WHERE id NOT IN ( SELECT * FROM ( SELECT id FROM TabTest GROUP BY factorA, factorB, factorC ) b );
-- 方案二 DELETE FROM TabTest WHERE id IN ( -- MySQL Error 1093 – Can‘t specify target table for update in FROM clause SELECT b.id FROM ( SELECT tOuter.`id` FROM TabTest tOuter INNER JOIN ( SELECT tInner.id, tInner.factorA, tInner.factorB, tInner.factorC FROM TabTest tInner GROUP BY tInner.factorA, tInner.factorB, tInner.factorC HAVING COUNT(1) > 1 ) a ON tOuter.`factorA` = a.`factorA` AND tOuter.`factorB` = a.`factorB` AND tOuter.`factorC` = a.`factorC` WHERE tOuter.`id` <> a.`id` )b )
方案一: 数据量小时, 比较便捷
方案二: 数据量大时使用, 第一个方案在70万数据下试过, 5分钟出不来结果, 放弃, 使用第二种方案, 秒完.
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原文地址:http://www.cnblogs.com/know-life-death/p/4671532.html