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累积聚合为聚合从序列内第一个元素到当前元素的数据，如为每个员工返回每月开始到现在累积的订单数量和平均订单数量
SELECT
a.empid,
a.ordermonth,a.qty AS thismonth,
SUM(b.qty) AS total,
CAST(AVG(b.qty) AS DECIMAL(5,2)) AS avg
FROM emporders a
INNER JOIN emporders b
ON a.empid=b.empid
AND b.ordermonth <= a.ordermonth
GROUP BY a.empid,a.ordermonth,a.qty
ORDER BY a.empid,a.ordermonth
WHERE DATE_FORMAT(a.ordermonth,‘%Y‘)=‘2015‘ AND DATE_FORMAT(b.ordermonth,‘%Y‘)=‘2015‘
SELECT
a.empid,
a.ordermonth,a.qty AS thismonth,
SUM(b.qty) AS total,
CAST(AVG(b.qty) AS DECIMAL(5,2)) AS avg
FROM emporders a
INNER JOIN emporders b
ON a.empid=b.empid
AND b.ordermonth <= a.ordermonth
WHERE DATE_FORMAT(a.ordermonth,‘%Y‘)=‘2015‘ AND DATE_FORMAT(b.ordermonth,‘%Y‘)=‘2015‘
GROUP BY a.empid,a.ordermonth,a.qty
HAVING total<1000
ORDER BY a.empid,a.ordermonth
这里并没有统计到达到1000时该月的情况，如果要进行统计，则情况又有点复杂。如果指定了total <= 1000，则只有该月订单数量正好为1000才进行统计，否则不会对该月进行统计。因此这个问题的过滤，可以从另外一个方面来考虑。当累积累积订单小于1000时，累积订单与上个月的订单之差是小于1000的，同时也能对第一个订单数量超过1000的月份进行统计。故该解决方案的SQL语句如下
SELECT
a.empid,
a.ordermonth,a.qty AS thismonth,
SUM(b.qty) AS total,
CAST(AVG(b.qty) AS DECIMAL(5,2)) AS avg
FROM emporders a
INNER JOIN emporders b
ON a.empid=b.empid
AND b.ordermonth <= a.ordermonth
WHERE DATE_FORMAT(a.ordermonth,‘%Y‘)=‘2015‘ AND DATE_FORMAT(b.ordermonth,‘%Y‘)=‘2015‘
GROUP BY a.empid,a.ordermonth,a.qty
HAVING total-a.qty < 1000
ORDER BY a.empid,a.ordermonth
SELECT
a.empid,
a.ordermonth,a.qty AS thismonth,
SUM(b.qty) AS total,
CAST(AVG(b.qty) AS DECIMAL(5,2)) AS avg
FROM emporders a
INNER JOIN emporders b
ON a.empid=b.empid
AND b.ordermonth <= a.ordermonth
WHERE DATE_FORMAT(a.ordermonth,‘%Y‘)=‘2015‘ AND DATE_FORMAT(b.ordermonth,‘%Y‘)=‘2015‘
GROUP BY a.empid,a.ordermonth,a.qty
HAVING total-a.qty < 1000 AND total >= 1000
ORDER BY a.empid,a.ordermonth
运行结果如下
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原文地址：http://www.cnblogs.com/chenqionghe/p/4679745.html
