oracle case where 复杂sql语句

         update hr_user u set u.is_approve=(case
         when u.curr_org_id in
              (select t.org_id
                 from hr_organization t
                start with t.org_id = 10001263
               connect by prior org_id = t.org_id_parent) then
          ‘N‘
         ELSE
          ‘Y‘
       END);
       
       
        update hr_user u set u.is_approve=(case
         when u.curr_org_id in
              (select t.org_id
                 from hr_organization t
                start with t.org_id = 10001263
               connect by prior org_id = t.org_id_parent) then
          ‘N‘
         ELSE
          ‘Y‘
       END) where u.EMP_NUM=‘066001‘;