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leetcode原文引用：
Given a Weather table, write a SQL query to find all dates‘ Ids with
higher temperature compared to its previous (yesterday‘s) dates.
+---------+------------+------------------+
| Id(INT) | Date(DATE) | Temperature(INT) |
+---------+------------+------------------+
| 1 | 2015-01-01 | 10 |
| 2 | 2015-01-02 | 25 |
| 3 | 2015-01-03 | 20 |
| 4 | 2015-01-04 | 30 |
+---------+------------+------------------+
For example, return the following Ids for the above Weather table:
+----+
| Id |
+----+
| 2 |
| 4 |
+----+
我的sql语句如下：
select t2.id from Weather t1 inner join Weather t2 on t1.Temperature < t2.temperature and to_days(t1.Date) = to_days(t2.Date)-1
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leetcode数据库sql之Rising Temperature
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原文地址：http://blog.csdn.net/zkn_cs_dn_2013/article/details/47280075
