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一、多线程不安全方式实现
public sealed class SingleInstance
{
private static SingleInstance instance;
private SingleInstance() { }
public static SingleInstance Instance
{
get
{
if (null == instance)
{
instance = new SingleInstance();
}
return instance;
}
}
}
sealed表示SingleInstance不能被继承。其实构造函数私有化已经达到了这个效果，私有的构造函数不能被继承。为了可读性，可以加个sealed。
不安全的单例指的是在多线程环境下可能有多个线程同时进入if语句，创建了多次单例对象。
二、安全的单例模式
public sealed class SingleInstance
{
private static volatile SingleInstance instance;
private static readonly object obj = new object();
private SingleInstance() { }
public static SingleInstance Instance
{
get
{
if (null == instance)
{
lock (obj)
{
if (null == instance)
{
instance = new SingleInstance();
}
}
}
return instance;
}
}
}
加锁保护，在多线程下可以确保实例值被创建一次。缺点是每次获取单例，都要进行判断，涉及到的锁和解锁比较耗资源。
三、只读属性式
public sealed class SingleInstance
{
private static readonly SingleInstance instance = new SingleInstance();
private SingleInstance() { }
public static SingleInstance Instance
{
get
{
return instance;
}
}
}
借助readonly属性，instance只被初始化一次，同样达到了单例的效果。在Main函数执行第一句话之前，instance其实已经被赋值了，并不是预期的 只有到访问Instance变量时才创建对象。
如下代码：
class Program
{
static void Main(string[] args)
{
Console.WriteLine("Begin");
var temp = SingleInstance.instance; ;
}
}
public sealed class SingleInstance
{
public static readonly SingleInstance instance = new SingleInstance();
private SingleInstance()
{
Console.WriteLine("初始化初始化！");
}
public static SingleInstance Instance
{
get { return instance; }
}
}
输出：
在执行第一句代码之前，实例已经被初始化。
解决方法是在SingleInstance中加上静态构造函数。
public sealed class SingleInstance
{
public static readonly SingleInstance instance = new SingleInstance();
static SingleInstance() { }
private SingleInstance()
{
Console.WriteLine("初始化初始化！");
}
public static SingleInstance Instance
{
get { return instance; }
}
}
在运行输出：
四、使用Lazy
public sealed class SingleInstance
{
private static readonly Lazy<SingleInstance> instance = new Lazy<SingleInstance>(() => new SingleInstance());
private SingleInstance(){}
public static SingleInstance Instance
{
get
{
return instance.Value;
}
}
}
Lazy默认是线程安全的。MSDN描述如下：
Will the lazily initialized object be accessed from more than one thread? If so, the Lazy<T> object might create it on any thread. You can use one of the simple constructors whose default behavior is to create a thread-safe Lazy<T> object, so that only one instance of the lazily instantiated object is created no matter how many threads try to access it. To create a Lazy<T> object that is not thread safe, you must use a constructor that enables you to specify no thread safety.
五、泛型单例
class Program
{
static void Main(string[] args)
{
Console.WriteLine("Begin");
mySingle.Instance.age = 500;
Console.WriteLine(mySingle.Instance.age);
}
}
public abstract class SingleInstance<T>
{
private static readonly Lazy<T> _instance = new Lazy<T>(() =>
{
var ctors = typeof(T).GetConstructors(BindingFlags.Instance| BindingFlags.NonPublic| BindingFlags.Public);
if (ctors.Count() != 1)
throw new InvalidOperationException(String.Format("Type {0} must have exactly one constructor.", typeof(T)));
var ctor = ctors.SingleOrDefault(c => c.GetParameters().Count() == 0 && c.IsPrivate);
if (ctor == null)
throw new InvalidOperationException(String.Format("The constructor for {0} must be private and take no parameters.", typeof(T)));
return (T)ctor.Invoke(null);
});
public static T Instance
{
get{ return _instance.Value;}
}
}
public class mySingle : SingleInstance<mySingle>
{
private mySingle() { }
public int age;
}
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原文地址：http://www.cnblogs.com/lh218/p/4713599.html
