Spring定时任务配置

@Repository
public class QuartzScore {
    
    public void runScore(){
        System.out.println("定时任务正在执行。。。。。。");
        System.out.println("当前时间： "+new SimpleDateFormat("yyyy年MM月dd日 HH:mm:ss").format(new Date()));
    }
}

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="
        http://www.springframework.org/schema/beans     
        http://www.springframework.org/schema/beans/spring-beans-3.2.xsd
        http://www.springframework.org/schema/context
        http://www.springframework.org/schema/context/spring-context-3.2.xsd">

    <!-- 要调用的工作类 -->
    <bean id="score" class="com.biiway.gmrcgrade.scorequartr.quartr.QuartzScore">
    </bean>

    <!-- 定义调用对象和调用对象的方法 -->
    <bean id="jobtask" class="org.springframework.scheduling.quartz.MethodInvokingJobDetailFactoryBean">
        <!-- 调用的类 -->
        <property name="targetObject" ref="score" />
        <!-- 调用类中的方法 -->
        <property name="targetMethod" value="runScore" />
    </bean>

    <!-- 定义触发时间 -->
    <bean id="doTime" class="org.springframework.scheduling.quartz.CronTriggerBean">
        <property name="jobDetail" ref="jobtask" />
        <!-- cron表达式,每天1,12点触发(0 0 1,12 ? * *) -->
        <property name="cronExpression" value="0/5 * * * * ?" />
    </bean>

    <!-- 总管理类 如果将lazy-init=‘false‘那么容器启动就会执行调度程序 -->
    <bean id="startQuertz" lazy-init="false" autowire="no"
        class="org.springframework.scheduling.quartz.SchedulerFactoryBean">
        <property name="triggers" ref="doTime" />
    </bean>


</beans>