标签:
Musical Theme
Time Limit: 20 Sec
Memory Limit: 256 MB
题目连接
http://poj.org/problem?id=1743
Description
Input
Output
For each test case, the output file should contain a single line with a single integer that represents the length of the longest theme. If there are no themes, output 0.
Sample Input
30
25 27 30 34 39 45 52 60 69 79 69 60 52 45 39 34 30 26 22 18
82 78 74 70 66 67 64 60 65 80
0
Sample Output
5
HINT
题意
让你找到最长的不相交重复子串
题解:
后缀数组,跑出height数组之后,然后直接二分然后O(n),check就好了
代码:
//qscqesze #include <cstdio> #include <cmath> #include <cstring> #include <ctime> #include <iostream> #include <algorithm> #include <set> #include <vector> #include <sstream> #include <queue> #include <typeinfo> #include <fstream> #include <map> #include <stack> typedef long long ll; using namespace std; //freopen("D.in","r",stdin); //freopen("D.out","w",stdout); #define sspeed ios_base::sync_with_stdio(0);cin.tie(0) #define maxn 25000 #define mod 10007 #define eps 1e-9 int Num; char CH[20]; //const int inf=0x7fffffff; //нчоч╢С const int inf=0x3f3f3f3f; inline ll read() { int x=0,f=1;char ch=getchar(); while(ch<‘0‘||ch>‘9‘){if(ch==‘-‘)f=-1;ch=getchar();} while(ch>=‘0‘&&ch<=‘9‘){x=x*10+ch-‘0‘;ch=getchar();} return x*f; } //************************************************************************************** int s[2*maxn]; int a[maxn]; int n; int sa[maxn], rank[maxn], height[maxn]; int wa[maxn], wb[maxn], wv[maxn], wd[maxn]; int cmp(int *r, int a, int b, int l){ return r[a] == r[b] && r[a+l] == r[b+l]; } void build_sa(int *r, int n, int m){ // 倍增算法 r为待匹配数组 n为总长度 m为字符范围 int i, j, p, *x = wa, *y = wb, *t; for(i = 0; i < m; i ++) wd[i] = 0; for(i = 0; i < n; i ++) wd[x[i]=r[i]] ++; for(i = 1; i < m; i ++) wd[i] += wd[i-1]; for(i = n-1; i >= 0; i --) sa[-- wd[x[i]]] = i; for(j = 1, p = 1; p < n; j *= 2, m = p){ for(p = 0, i = n-j; i < n; i ++) y[p ++] = i; for(i = 0; i < n; i ++) if(sa[i] >= j) y[p ++] = sa[i] - j; for(i = 0; i < n; i ++) wv[i] = x[y[i]]; for(i = 0; i < m; i ++) wd[i] = 0; for(i = 0; i < n; i ++) wd[wv[i]] ++; for(i = 1; i < m; i ++) wd[i] += wd[i-1]; for(i = n-1; i >= 0; i --) sa[-- wd[wv[i]]] = y[i]; for(t = x, x = y, y = t, p = 1, x[sa[0]] = 0, i = 1; i < n; i ++){ x[sa[i]] = cmp(y, sa[i-1], sa[i], j) ? p - 1: p ++; } } } void calHeight(int *r, int n){ // 求height数组。 int i, j, k = 0; for(i = 1; i <= n; i ++) rank[sa[i]] = i; for(i = 0; i < n; height[rank[i ++]] = k){ for(k ? k -- : 0, j = sa[rank[i]-1]; r[i+k] == r[j+k]; k ++); } } int check(int mid) { int Minn=sa[0],Maxn=sa[0]; for(int i=0;i<=n;i++) { if(height[i]>=mid) { Minn=min(sa[i],Minn); Maxn=max(sa[i],Maxn); if(Maxn-Minn>mid) return 1; } else Minn=Maxn=sa[i]; } return 0; } void init() { memset(a,0,sizeof(a)); memset(s,0,sizeof(s)); memset(sa,0,sizeof(sa)); memset(rank,0,sizeof(rank)); memset(height,0,sizeof(height)); memset(wa,0,sizeof(wa)); memset(wb,0,sizeof(wb)); memset(wv,0,sizeof(wv)); memset(wd,0,sizeof(wd)); } int main() { while(cin>>n) { if(n==0) break; init(); for(int i=0;i<n;i++) a[i]=read(); n--; for(int i=0;i<n;i++) s[i]=a[i+1]-a[i]+100; s[n]=0; build_sa(s,n+1,200); calHeight(s,n); int l=0,r=n,ans=0; while(l<=r) { int mid=(l+r)>>1; if(check(mid)) { ans=max(ans,mid); l=mid+1; } else r=mid-1; } if(ans<4) ans=0; else ans++; cout<<ans<<endl; } }
POJ 1743 Musical Theme 后缀数组 最长重复不相交子串
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原文地址:http://www.cnblogs.com/qscqesze/p/4719232.html