TypeError:'stepUp' called on an object that does not implement interface HTMLInputElement.

标签：javascript   mysql   springmvc   

1、错误描述

2、错误原因

$.ajax({
      type:"post",
      url:"/user/queryUserInfo",
      dataType:"json",
      data:{
          "userId":$("#userID").val(),
          "num":num,
          "type":$("#type").val()
      },
      success:function(resp){

      }
});

3、解决办法

var num = 0;
if($("#type").val() == "1")
{
     num = $("#num").val();
}
else
{
     num = 0;
}

$.ajax({
      type:"post",
      url:"/user/queryUserInfo",
      dataType:"json",
      data:{
          "userId":$("#userID").val(),
          "num":num,
          "type":$("#type").val()
      },
      success:function(resp){

      }
});

TypeError:'stepUp' called on an object that does not implement interface HTMLInputElement.

标签：javascript   mysql   springmvc   

原文地址：http://blog.csdn.net/you23hai45/article/details/47617419