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根据经纬度坐标获取对应的切片算法

时间:2015-08-15 01:32:48      阅读:2685      评论:0      收藏:0      [点我收藏+]

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根据经纬度坐标获取对应的切片算法,含天地图、谷歌等。

Javascript:

  1 function getPoints2()
  2 {
  3     var topTileFromX  = -180;
  4     var topTileFromY  =  90;
  5     
  6     var tdtScale={18:5.36441802978515E-06,17:1.07288360595703E-05,16:2.1457672119140625E-05,15:4.29153442382814E-05,14:8.58306884765629E-05,13:0.000171661376953125,12:0.00034332275390625,11:0.0006866455078125,10:                  0.001373291015625,9:0.00274658203125,8:0.0054931640625,7:0.010986328125,6:0.02197265625,5:0.0439453125,4:0.087890625,3:0.17578125,2:0.3515625,1:0.703125};    
  7                  
  8     var strList = document.getElementById("content").value;
  9     
 10     
 11     var oStringList = strList.split(‘,‘);
 12     var level  = oStringList[0];
 13     var lon    =  oStringList[1];
 14     var lat   =  oStringList[2];
 15    
 16   
 17        var coef =  tdtScale[level]*256;
 18             
 19     var x_num =  Math.round((lon - topTileFromX) / coef);
 20     var y_num =  Math.round((topTileFromY - lat) / coef); 
 21     
 22    //  var dir =  "http://t7.tianditu.com/DataServer?T=vec_c&";
 23     // var server = "l="+String(level)+"&"+"x="+String(x_num)+"&"+"y="+String(y_num);
 24     
 25     
 26     var  dir = "http://t1.tianditu.cn/vec_c/wmts?SERVICE=WMTS&REQUEST=GetTile&STYLE=default&VERSION=1.0.0&LAYER=vec&TILEMATRIXSET=c&";    
 27      var server = "TILEMATRIX="+String(level)+"&"+"TILEROW="+String(y_num)+"&"+"TILECOL="+String(x_num)+"&FORMAT=tiles";
 28         
 29      
 30      var imageDir = dir+server;
 31 
 32      
 33     // alert(imageDir);
 34      
 35      var imgDiv = document.getElementById("map");
 36      imgDiv.style.backgroundImage =  "url("+imageDir+")";
 37    
 38       
 39 
 40 }
 41 
 42 
 43 function lon2Mercator(px)
 44 {
 45     var x = px * 20037508.3427892 / 180;
 46     return x;
 47 }
 48 
 49  function lat2Mercator(py)
 50         {
 51             
 52             var y;
 53             y = Math.log(Math.tan((90 + py) * Math.PI / 360)) / (Math.PI / 180);
 54         
 55             y = y * 20037508.3427892 / 180;
 56         
 57             return y;
 58         }
 59 
 60 function getPoints3()
 61 {
 62     
 63     
 64     var topTileFromX  = -20037508.3427892;
 65     var topTileFromY  =  20037508.3427892;
 66     
 67     var tdtScale={18:0.597164283559817,17:1.19432856685505,16:2.38865713397468,15:4.77731426794937,14:9.55462853563415,13:19.1092570712683,12:38.2185141425366,11:76.4370282850732,10:152.8740565704,9:305.7481128,8:611.49622628138,7:1222.99245256249,6:2445.98490512499,5:4891.96981024998,4:9783.93962049996,3:19567.8792409999,2:39135.7584820001,1:78271.5169639999};    
 68                  
 69     var strList = document.getElementById("content").value;
 70     
 71     
 72     var oStringList = strList.split(‘,‘);
 73     var level  = oStringList[0];
 74     var lon    =  oStringList[1];
 75     var lat    =  oStringList[2];
 76 
 77     lon = lon2Mercator(parseFloat(lon));
 78     lat = lat2Mercator(parseFloat(lat));
 79    
 80        var coef =  tdtScale[level]*256;
 81             
 82     var x_num =  Math.round((lon - topTileFromX) / coef);
 83     var y_num =  Math.round((topTileFromY - lat) / coef); 
 84     
 85    //  var dir =  "http://t7.tianditu.com/DataServer?T=vec_c&";
 86     // var server = "l="+String(level)+"&"+"x="+String(x_num)+"&"+"y="+String(y_num);
 87     
 88     
 89     //var  dir = "http://t0.tianditu.cn/vec_w/wmts?SERVICE=WMTS&REQUEST=GetTile&STYLE=default&VERSION=1.0.0&LAYER=vec&TILEMATRIXSET=c&";    
 90     // var server = "TILEMATRIX="+String(level)+"&"+"TILEROW="+String(y_num)+"&"+"TILECOL="+String(x_num)+"&FORMAT=tiles";
 91         
 92        var dir =  "http://t0.tianditu.com/DataServer?T=vec_w&";
 93       var server = "l="+String(level)+"&"+"x="+String(x_num)+"&"+"y="+String(y_num);
 94       
 95 
 96     
 97      var imageDir = dir+server;
 98      
 99      
100      var imgDiv = document.getElementById("map");
101      imgDiv.style.backgroundImage =  "url("+imageDir+")";
102    
103       
104 
105 }
106 
107 
108 function getPoints4()
109 {
110 
111     var topTileFromX  = -20037508.3427892;
112     var topTileFromY  =  20037508.3427892;
113     
114     var tdtScale={18:0.597164283559817,17:1.19432856685505,16:2.38865713397468,15:4.77731426794937,14:9.55462853563415,13:19.1092570712683,12:38.2185141425366,11:76.4370282850732,10:152.8740565704,9:305.7481128,8:611.49622628138,7:1222.99245256249,6:2445.98490512499,5:4891.96981024998,4:9783.93962049996,3:19567.8792409999,2:39135.7584820001,1:78271.5169639999};    
115                  
116     var strList = document.getElementById("content").value;
117     
118     
119     var oStringList = strList.split(‘,‘);
120     var level  = oStringList[0];
121     var lon    =  oStringList[1];
122     var lat    =  oStringList[2];
123 
124     lon = lon2Mercator(parseFloat(lon));
125     lat = lat2Mercator(parseFloat(lat));
126    
127        var coef =  tdtScale[level]*256;
128             
129     var x_num =  Math.round((lon - topTileFromX) / coef);
130     var y_num =  Math.round((topTileFromY - lat) / coef); 
131     
132 
133        var dir =  "http://a.tile.openstreetmap.org/";
134       var server = String(level)+"/"+String(x_num)+"/"+String(y_num)+".png";
135       
136     
137      var imageDir = dir+server;
138 
139      
140      var imgDiv = document.getElementById("map");
141      imgDiv.style.backgroundImage =  "url("+imageDir+")";
142    
143       
144 
145 }
146 
147 function getPoints5()
148 {
149 
150     var topTileFromX  = -20037508.3427892;
151     var topTileFromY  =  20037508.3427892;
152     
153     var tdtScale={18:0.597164283559817,17:1.19432856685505,16:2.38865713397468,15:4.77731426794937,14:9.55462853563415,13:19.1092570712683,12:38.2185141425366,11:76.4370282850732,10:152.8740565704,9:305.7481128,8:611.49622628138,7:1222.99245256249,6:2445.98490512499,5:4891.96981024998,4:9783.93962049996,3:19567.8792409999,2:39135.7584820001,1:78271.5169639999};    
154                  
155     var strList = document.getElementById("content").value;
156     
157     
158     var oStringList = strList.split(‘,‘);
159     var level  = oStringList[0];
160     var lon    =  oStringList[1];
161     var lat    =  oStringList[2];
162 
163     lon = lon2Mercator(parseFloat(lon));
164     lat = lat2Mercator(parseFloat(lat));
165    
166        var coef =  tdtScale[level]*256;
167             
168     var x_num =  Math.round((lon - topTileFromX) / coef);
169     var y_num =  Math.round((topTileFromY - lat) / coef); 
170     
171 
172         
173        var dir =  "http://mt2.google.cn/vt/lyrs=m@167000000&hl=zh-CN&gl=cn&";
174       var server = "x="+String(x_num)+"&"+"y="+String(y_num)+"&"+"z="+String(level)+"&s=Galil";
175       
176 
177     
178      var imageDir = dir+server;
179      
180      
181      var imgDiv = document.getElementById("map");
182      imgDiv.style.backgroundImage =  "url("+imageDir+")";
183    
184       
185 
186 }


测试HTML:

 1 <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
 2 <html xmlns="http://www.w3.org/1999/xhtml">
 3 
 4     <head>  
 5     <meta http-equiv="Content-Type" content="text/html; charset=gb2312">
 6     <title>获取瓦片</title>  
 7     <style>
 8 v\:*   {  Behavior:   url(#default#VML)} 
 9 </style>
10     <link href="default.css" rel="stylesheet" type="text/css" media="screen" />  
11     </head>  
12      <script language="javascript" src="Tool.js"></script>
13     <body>  
14     
15       <input id="content" type="text" autocomplete="on" maxlength="100" size="35"> 
16 <input type="button" value="获取天地图经纬度" onClick="getPoints2();"/> <input type="button" value="获取天地图墨卡托" onClick="getPoints3();"/> <input type="button" value="获取OpenstreetMap" onClick="getPoints4();"/>     
17  <input type="button" value="获取谷歌地图" onClick="getPoints5();"/>  
18          <div id="map"> </div>  
19          
20  <script type="text/javascript"> 
21  
22 
23      document.getElementById("content").value = "10,113.6,34.8";        
24                   
25    </script>
26   
27   </body>  

 

根据经纬度坐标获取对应的切片算法

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原文地址:http://www.cnblogs.com/lohcve/p/4731587.html

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