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5. Longest Palindromic Substring
Brutal Force: O(n^2) Manacher: O(n) ...
分类:其他好文   时间:2017-09-21 15:53:52    阅读次数:109
Leetcode Hashtable 1-5
JAVA: 3. Longest Substring Without Repeating Characters 以前一直想找到一种数组,不用事先规定大小,可以直接插入,现在发现了,可以用hashset,但是无法知道位置信息 可以用这个 int[26] for Letters 'a' - 'z' or ...
分类:其他好文   时间:2017-09-19 11:16:38    阅读次数:147
3. Longest Substring Without Repeating Characters
Given a string, find the length of the longest substring without repeating characters. Examples: Given "abcabcbb", the answer is "abc", which the leng... ...
分类:其他好文   时间:2017-09-19 11:07:00    阅读次数:131
ORACLE中seq$表更新频繁的分析
在分析ORACLE的AWR报告时,发现SQL ordered by Executions(记录了按照SQL的执行次数排序的TOP SQL。该排序可以看出监控范围内的SQL执行次数)下有一个SQL语句执行非常频繁,一个小时执行了上万次: update seq$ set increment$=:2, m ...
分类:数据库   时间:2017-09-19 00:11:40    阅读次数:329
题四:给字符加千分号
<script>//给字符加千分号 function live(str){ //判断字符串是否被3整除 var num=str.length%3; //复制不被3整除的前num个数 var xstr=str.substring(0,num); //复制被3整除的数 var dstr=str.subs ...
分类:其他好文   时间:2017-09-18 12:17:55    阅读次数:118
674. Longest Continuous Increasing Subsequence
Given an unsorted array of integers, find the length of longest continuous increasing subsequence. Example 1: Example 2: 在未排序的数组中,找出最长递增序列的长度 c++(16ms ...
分类:其他好文   时间:2017-09-16 17:20:37    阅读次数:141
LeetCode Number of Longest Increasing Subsequence
原题链接在这里:https://leetcode.com/problems/number-of-longest-increasing-subsequence/description/ 题目: Given an unsorted array of integers, find the number o ...
分类:其他好文   时间:2017-09-16 13:34:11    阅读次数:134
[GeeksForGeeks] Diameter of a Binary Tree
The diameter of a tree (sometimes called the width) is the number of nodes on the longest path between two leaves in the tree. The diagram below shows ...
分类:其他好文   时间:2017-09-15 10:09:43    阅读次数:147
spoj1812 LCS2 - Longest Common Substring II
地址:http://www.spoj.com/problems/LCS2/ 题面: LCS2 - Longest Common Substring II no tags no tags A string is finite sequence of characters over a non-empt ...
分类:其他好文   时间:2017-09-14 10:34:44    阅读次数:158
Longest Continuous Increasing Subsequence
这道题为简单题 题目: 思路: 设置三个变量,max_long 存储总的最大长度,l代表该值目前的最大长度,num主要用来比较列表的前后大小。如果i大于num那么l就一直加1.否则l就和max_long比较大小,l变为1,num更新为i值 代码: ...
分类:其他好文   时间:2017-09-14 00:32:17    阅读次数:148
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