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hdu 3262 09 宁波 现场 C - Seat taking up is tough 暴力
DescriptionStudents often have problems taking up seats. When two students want the same seat, a quarrel will probably begin.It will have very bad eff...
分类:其他好文   时间:2014-11-11 18:58:37    阅读次数:322
zoj 1425 最大交叉匹配
Crossed MatchingsTime Limit: 2 Seconds Memory Limit: 65536 KBThere are two rows of positive integer numbers. We can draw one line segment between any....
分类:其他好文   时间:2014-11-11 18:49:49    阅读次数:199
A + B Again
Problem DescriptionThere must be many A + B problems in our HDOJ , now a new one is coming.Give you two hexadecimal integers , your task is to calcula...
分类:其他好文   时间:2014-11-11 18:28:42    阅读次数:130
Android 学习之显式激活与隐式激活Activity
在res界面里面有两个布局文件activity_main和acivity_twoactivity_main里面有如下四个按钮 acivity_two.xml 现在我们需要点击main里面的"跳转到第二个页面",让程序显示地跳转到t...
分类:移动开发   时间:2014-11-11 15:49:21    阅读次数:282
poj3414--Pots(bfs,记录路径)
Pots Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 10149   Accepted: 4275   Special Judge Description You are given two pots, having the volume of A and ...
分类:其他好文   时间:2014-11-11 14:27:12    阅读次数:313
LeetCode:Median of Two Sorted Arrays
题目描述: There are two sorted arrays A and B of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). 思路:写一个找两个数组中第k大数的函数,...
分类:其他好文   时间:2014-11-11 12:45:34    阅读次数:205
【转】c# 类反射简单操作
转:http://www.jb51.net/article/25863.htm首先建立一个测试的类复制代码代码如下:public class MyClass{public int one { set; get; }public int two { set; get; }public int five...
分类:Windows程序   时间:2014-11-11 12:15:13    阅读次数:177
java里头几个重要的IO概念
## 同步与异步 阻塞还是不阻塞,轮询还是事件驱动 Netty是事件驱动的 ## Buffer and Stream > Java has two kinds of classes for input and output (I/O): streams and readers/writers. Streams (InputStream, ...
分类:编程语言   时间:2014-11-11 11:01:56    阅读次数:218
[LeetCode] Divide Two Integers
Divide two integers without using multiplication, division and mod operator. 显然,如果光用减法太慢。让商为N,那么需要用O(N)的时间。这里要求比较苛刻,连乘法都不能使用,所以只能寄希望于二进制操作了。 这里可以把除数表示为:dividend = 2^i * divisor + 2^(i-1) * divisor +...
分类:其他好文   时间:2014-11-11 02:02:27    阅读次数:214
[LeetCode] Divide Two Integers
Divide two integers without using multiplication, division and mod operator.显然,如果光用减法太慢。让商为N,那么需要用O(N)的时间。这里要求比较苛刻,连乘法都不能使用,所以只能寄希望于二进制操作了。这里可以把除数表示为:...
分类:其他好文   时间:2014-11-11 01:57:47    阅读次数:215
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