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Find Peak Element
Find Peak ElementA peak element is an element that is greater than its neighbors.Given an input array wherenum[i] ≠ num[i+1], find a peak element and ...
分类:其他好文   时间:2014-12-18 20:34:49    阅读次数:169
Visitor
#include #include using namespace std;#define DESTROY_POINTER(ptr) if (ptr) { delete ptr; ptr = NULL; }class Element;class Visitor{public: virtual ...
分类:其他好文   时间:2014-12-18 18:18:30    阅读次数:186
使用自定义选择器
jQuery允许我们在css选择器的基础上定义自定义选择器来让我们的代码更简洁;下面是使用方法和参数说明: 1 $.expr[':'].mycustomselector= function(element, index, meta, stack){ 2 // element- DOM元素 3...
分类:其他好文   时间:2014-12-18 14:59:14    阅读次数:199
博客园客户端(Universal App)开发随笔 -- App的精灵:自定义控件
前言 拿到一个App的需求后,对于前端工程师来说,第一步要干什么?做Navigation规划!第二步要干什么?做页面分解!页面分解如何做?首先要确定UI Element的容器,其次要抽象UI Element本身,也就是要做一堆自定义控件,最终组成整个页面。今天我们就说说自定义控件如何实现吧。 感性认...
分类:移动开发   时间:2014-12-18 14:50:19    阅读次数:323
leetcode------Remove Duplicates from Sorted Array
标题:Remove Duplicates from Sorted Array通过率:31.9%难度简单Given a sorted array, remove the duplicates in place such that each element appear onlyonceand retu...
分类:其他好文   时间:2014-12-18 14:49:05    阅读次数:175
SyntaxError: missing ] after element list 火狐问题
关于火狐执行var obj = eval('(' + data + ')');时 报SyntaxError: missing ] after element list错误,Chrome和IE正常情形如下:当使用ajax接收从后台传递过来的json数据时$.ajax( { type : "POST", dataType : "json", url : "RegisterAction.actio...
分类:其他好文   时间:2014-12-18 00:22:24    阅读次数:165
Leetcode: Find Peak Element
A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in ...
分类:其他好文   时间:2014-12-18 00:17:44    阅读次数:146
[LeetCode]Single Number II
Given an array of integers, every element appears three times except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without usi...
分类:其他好文   时间:2014-12-17 22:45:19    阅读次数:215
【Leetcode】:Min Stack
题目链接:https://oj.leetcode.com/problems/min-stack/ Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack.pop(...
分类:其他好文   时间:2014-12-17 16:28:46    阅读次数:181
leetcode------Remove Element
标题:Remove Element通过率:32.6%难度:简单Given an array and a value, remove all instances of that value in place and return the new length.The order of elements...
分类:其他好文   时间:2014-12-17 12:30:18    阅读次数:157
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