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C++之 什么是对象
What is an object?object=entityobjects=attributes+servicesData: the properties or status < Operations: the functionsMappingFrom the problem space to t...
分类:编程语言   时间:2014-11-01 21:42:40    阅读次数:236
POJ3414Pots【BFS】
大意:有两个杯子 三种操作You are given two pots, having the volume ofAandBliters respectively. The following operations can be performed:FILL(i) fill the poti(1 ≤...
分类:其他好文   时间:2014-11-01 09:42:07    阅读次数:332
监控sql执行时剩余时间
--监控sql执行时剩余时间 你知道正在运行的sql大概需要多长时间么? 你知道正在运行的sql大概完成了百分之几么? 你知道正在运行的sql大概还要多长时间完成么? V$SESSION_LONGOPS帮你忙。 V$SESSION_LONGOPS在官方文档中的描述: V$SESSION_LONGOPS displays the status of various operations th...
分类:数据库   时间:2014-10-30 15:23:56    阅读次数:241
实现Operations Manager 2012 R2单一部署
单一服务器管理组方案结合了可在WindowsServer2012或WindowsServer2012R2操作系统(作为ActiveDirectory域中的成员服务器运行)的单一实例上共存的所有管理组角色。此实例可位于专用硬件上或虚拟计算机上。可以将操作控制台部署到单一服务器以外的其他计算机上,并且可以通过浏..
分类:其他好文   时间:2014-10-29 02:10:08    阅读次数:299
安装Operations Manager代理程序(1)
OperationsManager“代理”是安装在计算机上的一项服务。代理会收集数据、将采样数据与预定义的值进行比较、创建警报并运行响应。管理服务器会接收配置并将配置分发到受监视的计算机上的代理。你可以使用一些方法在计算机上安装OperationsManager代理。(1)可以在操作控制台中..
分类:其他好文   时间:2014-10-29 02:05:05    阅读次数:282
Switch Game
Problem DescriptionThere are many lamps in a line. All of them are off at first. A series of operations are carried out on these lamps. On the i-th op...
分类:其他好文   时间:2014-10-29 01:39:28    阅读次数:433
面试题:实现LRUCache::Least Recently Used的缩写,意思是最近最少使用,它是一种Cache替换算法
Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations:getandset.get(key)- Get the valu...
分类:编程语言   时间:2014-10-25 22:57:35    阅读次数:480
2.App Components-Services
1.Services A Service is an application component that can perform long-running operations in the background and does not provide a user interface. A.....
分类:移动开发   时间:2014-10-24 23:32:15    阅读次数:428
LeetCode 146 LRU Cache
Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and set. get(key) - Get the value (will always be positive) of the key if ...
分类:系统相关   时间:2014-10-22 12:56:02    阅读次数:274
HDU - 4267 A Simple Problem with Integers(树状数组的逆操作)
Description Let A1, A2, ... , AN be N elements. You need to deal with two kinds of operations. One type of operation is to add a given number to a few numbers in a given interval. The other is to q...
分类:编程语言   时间:2014-10-18 16:59:56    阅读次数:321
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