我有这样的一个小算法,把数组中的所有的偶数或技术分别选择出来。很多人可能,会循环这个数组,而我恰恰不循环数组就能做到这一点,代码如下。
function odd($var)
{
// returns whether the input integer is odd
return($var & 1);
}
function even($var)
{
// ret...
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编程语言 时间:
2014-10-13 18:06:39
阅读次数:
230
UITableView 中的Cell选中相关的操作:在TableView中设置Cell相关:@property(nonatomic) BOOL allowsSelection NS_AVAILABLE_IOS(3_0); // default is YES. Controls whether ro....
分类:
移动开发 时间:
2014-10-13 14:04:49
阅读次数:
182
Problem:Determine whether an integer is a palindrome. Do this without extra space.click to show spoilers.Some hints:Could negative integers be palindr...
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其他好文 时间:
2014-10-13 12:18:49
阅读次数:
100
相同的雪花
时间限制:1000 ms | 内存限制:65535 KB
难度:4
描述You may have heard that no two snowflakes are alike. Your task is to write a program to determine whether this is really true. Your
program w...
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其他好文 时间:
2014-10-12 20:01:38
阅读次数:
277
[leetcode]Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center)....
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其他好文 时间:
2014-10-09 15:33:58
阅读次数:
193
Given s1, s2, s3, find whether s3 is formed by the interleaving of s1 and s2.
For example,
Given:
s1 = "aabcc",
s2 = "dbbca",
When s3 = "aadbbcbcac",
return true.
When s3 = "aadbbbaccc", retur...
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其他好文 时间:
2014-10-09 15:10:14
阅读次数:
179
Determine whether an integer is a palindrome. Do this without extra space.Some hints:Could negative integers be palindromes? (ie, -1)If you are thinki...
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其他好文 时间:
2014-10-07 19:09:53
阅读次数:
180
Given s1, s2, s3, find whether s3 is formed by the interleaving of s1 and s2.
For example,
Given:
s1 = "aabcc",
s2 = "dbbca",
When s3 = "aadbbcbcac", return true.
When s3 = "aadbbbaccc", ret...
分类:
其他好文 时间:
2014-10-06 17:31:39
阅读次数:
251
Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center).For example, this binary tree is symmetric: 1 / \ ...
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其他好文 时间:
2014-10-02 09:45:52
阅读次数:
184
Symmetric TreeGiven a binary tree, check whether it is a mirror of itself (ie, symmetric around its center).For example, this binary tree is symmetric...
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其他好文 时间:
2014-10-02 05:53:22
阅读次数:
170