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Codeforces Round #274 (Div. 2) E. Riding in a Lift(DP)
Imagine that you are in a building that has exactly n floors. You can move between the floors in a lift. Let's number the floors from bottom to top with integers from 1 to n. Now you're on the flo...
分类:其他好文   时间:2014-10-22 01:07:40    阅读次数:217
前端之Android入门(5) – MVC模式(下)
我们将 View 类单独出来并完成了设计和编写。这次我们将完成 Model 类,并通过 Controller 将两者连接起来,完成这个计算器程序。模型(Model)就是程序中封装了数据,并定义了操作和处理这些数据的逻辑的对象。在计算器的例子中,就是处理输入的操作数和运算符,并计算返回结果。Let’s...
分类:移动开发   时间:2014-10-21 10:11:36    阅读次数:244
HDU1067 Gap 【BFS+MAP】
Gap Time Limit: 20000/10000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 597    Accepted Submission(s): 327 Problem Description Let's play a card game...
分类:其他好文   时间:2014-10-21 07:50:00    阅读次数:176
Using text search in Web page with Sikuli
在網頁中如何使用Sikuli找特定字串呢?原理:我們可以使用 組合鍵 ctrl + 來放大網頁的比例,使得sikuli的OCR功能找的更清準實作:for i in range(4): type("+", KEY_CTRL)which = input() # Let user type the...
分类:Web程序   时间:2014-10-21 00:43:33    阅读次数:328
[HDU 1004]Let the Balloon Rise
字符串操作。#include #include using namespace std;const int max = 1000 + 10;int u,M,N;int cnt[max];char TTT[20] = "\n";char str[max][20]; void OutAns(){ ...
分类:其他好文   时间:2014-10-21 00:42:50    阅读次数:222
call/cc分析一例
(define (fact n) (let ((r 1) (k 'void)) (call/cc (lambda (c) (set! k c))) (set! r (* r n)) (set! n (- n 1)) (if (= n 1) r (k 'recurse)))...
分类:其他好文   时间:2014-10-19 21:15:46    阅读次数:199
URAL 1306-Sequence Median(堆)
1306. Sequence Median Time limit: 1.0 second Memory limit: 1 MB Language limit: C, C++, Pascal Given a sequence of N nonnegative integers. Let's define the median of such sequence. If N is...
分类:其他好文   时间:2014-10-19 18:40:09    阅读次数:265
Move resources allocated using unmanaged interface to managed devm interface
转载:http://blog.csdn.net/swingboard/article/details/27207497So today let’s talk about devm functions as that is what I have been upto the past couple o...
分类:其他好文   时间:2014-10-18 19:38:24    阅读次数:292
HDU - 4267 A Simple Problem with Integers(树状数组的逆操作)
Description Let A1, A2, ... , AN be N elements. You need to deal with two kinds of operations. One type of operation is to add a given number to a few numbers in a given interval. The other is to q...
分类:编程语言   时间:2014-10-18 16:59:56    阅读次数:321
Linux shell编程札记
if-then的高级特性 [[]]、[]都是用来测试( 测试分为数值比较、字符串比较、文件比价 )的,[[]]是关键字,里面可以用&&、||、等类似C语言的语法;[]是bash内嵌的命令,也是用于测试的。[[]]通用性更好些。(()),类似let,用于计算表达式。()可以把多个命令括起来,在一个子....
分类:系统相关   时间:2014-10-18 13:49:12    阅读次数:243
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