题目描述 Farmer John's N (1 <= N <= 100,000) cows, conveniently numbered 1..N, are once again standing in a row. Cow i has height H_i (1 <= H_i <= 1,000,0 ...
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其他好文 时间:
2019-07-16 00:03:02
阅读次数:
105
Basic DP Problem URL:https://vjudge.net/problem/HDU-2018 Describe: There is a cow that gives birth to a heifer every year.Every heifer starts in the f ...
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其他好文 时间:
2019-07-14 13:06:30
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71
Cow Acrobats Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 7564 Accepted: 2822 Description Farmer John's N (1 <= N <= 50,000) cows (numbe ...
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其他好文 时间:
2019-07-14 12:48:03
阅读次数:
82
题目:poj.org/problem?id=3264 题意:求一段区间内最大值与最小值的差。 看到区间最值首先想到RMQ--ST算法。但本题出现在了kuangbin专题的线段树里。 用线段树也无思维难点,但有两个坑: 1. 查询函数中,区间不包含时的返回值。 2.用cin,cout会TLE。用c的输 ...
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其他好文 时间:
2019-07-13 13:22:03
阅读次数:
96
题目背景 [Usaco2008 Jan] [Usaco2008 Jan] 题目描述 N (1 ≤ N ≤ 100) cows, conveniently numbered 1..N, are participating in a programming contest. As we all know ...
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其他好文 时间:
2019-07-10 01:08:44
阅读次数:
92
题面 这题确实是一个近乎(就是)tarjan板子的一道题,也是少有不用缩点的题目 把题目翻译一下吧,就是说若一头奶牛身上的绳子以顺时针方向出去,一直遍历下去可以回来,就说明能够完成圆舞,及若一群奶牛在同一强连通分量中,则可以完成圆舞,而又因为只能顺时针访问,故有向(我之前当成无向图做居然能拿90分? ...
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其他好文 时间:
2019-07-09 12:09:24
阅读次数:
132
Calendar cal2 = Calendar.getInstance(); SimpleDateFormat sdf = new SimpleDateFormat("HH:mm:ss"); sdf.setTimeZone(TimeZone.getTimeZone("Asia/Dubai")); ... ...
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其他好文 时间:
2019-07-08 14:07:18
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114
题目描述 One cow from each of N farms (1 ≤ N ≤ 1000) conveniently numbered 1..N is going to attend the big cow party to be held at farm #X (1 ≤ X ≤ N). A ...
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其他好文 时间:
2019-07-08 13:44:14
阅读次数:
98
题目描述 The N (2 <= N <= 10,000) cows are so excited: it's prom night! They are dressed in their finest gowns, complete with corsages and new shoes. They ...
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其他好文 时间:
2019-07-08 00:35:52
阅读次数:
144