DescriptionThe cows have purchased a yogurt factory that makes world-famous Yucky Yogurt. Over the next N (1 #includeint min(int a,int b){ if(a>b) ...
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其他好文 时间:
2014-07-06 14:21:54
阅读次数:
215
Building roads
Time Limit: 2000MS
Memory Limit: 65536K
Total Submissions: 6229
Accepted: 2093
Description
Farmer John's farm has N barns, and there are some cows that...
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其他好文 时间:
2014-06-30 10:55:18
阅读次数:
146
【题目】
There are N gas stations along a circular route, where the amount of gas at station i is gas[i].
You have a car with an unlimited gas tank and it costs cost[i] of gas to travel from station i to its next station (i+1). You begin the journey with an ...
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其他好文 时间:
2014-06-26 13:27:05
阅读次数:
231
Description
The cows, as you know, have no fingers or thumbs and thus are unable to play Scissors, Paper, Stone' (also known as 'Rock, Paper, Scissors', 'Ro, Sham, Bo', and a host of other names) i...
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其他好文 时间:
2014-06-22 17:15:11
阅读次数:
275
Layout
Time Limit: 1000MS
Memory Limit: 65536K
Total Submissions: 6582
Accepted: 3182
Description
Like everyone else, cows like to stand close to their friends when que...
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其他好文 时间:
2014-06-21 23:54:18
阅读次数:
307
Picnic Cows
Time Limit: 8000/4000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 1563 Accepted Submission(s): 478
Problem Description
It’s summer voc...
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其他好文 时间:
2014-06-10 07:00:32
阅读次数:
262
poj2186Popular
Cows分析:直接求一下强连通分量,对于同一个强连通分量里面的结点状态是相同的,要求有多少个人被其他所有的人都认可,只有可能是拓扑排序的最后一个强连通的结点个数,判断一下其他节点是否都可以到该联通分量就ok了。
1 #include 2 #include 3 #in.....
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其他好文 时间:
2014-06-08 21:44:25
阅读次数:
307
链接:
POJ 2186 Popular Cows
题意:
每一头牛都希望在牛群里面备受瞩目,在一个牛群中有N头牛(1
输入:
第一行两个整数 N 和 M
第2 到 M + 1 行,两个分开的数 A,B,意味着 A认为 B 更受欢迎。
输出:
被所有牛认为受欢迎的牛的个数
比如输入:
3 3
1 2
2 1...
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其他好文 时间:
2014-06-08 18:20:40
阅读次数:
204
Description
Farmer John wants the cows to prepare for the county jumping competition, so Bessie and the gang are practicing jumping over hurdles. They are getting tired, though, so they want to be ...
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其他好文 时间:
2014-06-08 15:55:10
阅读次数:
199
http://poj.org/problem?id=3621
大致题意:给出一个有向图,每个点都有一个点权,每条有向边也都有一个边权,要求出一个环使得环中点权之和与边权之和的比值最大。
思路:和最优比率生成树异曲同工。设点权是v[i],边权是e[i]。不同的是这里一个是点,一个是边。怎么像生成树一样把这两个值放到一起呢?可以把他们都转化到边上。同样的二分λ,每次给边重新赋权为v...
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其他好文 时间:
2014-06-05 03:30:56
阅读次数:
191