Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.
push(x) -- Push element x onto stack.pop() -- Removes the element on top of the stack.top() -- Get ...
分类:
其他好文 时间:
2015-07-20 09:16:26
阅读次数:
96
Implement the following operations of a queue using stacks.
push(x) -- Push element x to the back of queue.pop() -- Removes the element from in front of queue.peek() -- Get the front element.empty(...
分类:
其他好文 时间:
2015-07-18 11:03:29
阅读次数:
99
Question:Implement the following operations of a stack using queues.push(x) -- Push element x onto stack.pop() -- Removes the element on top of the st...
分类:
其他好文 时间:
2015-07-17 07:07:50
阅读次数:
115
原题如下:
Implement the following operations of a stack using queues.
push(x) -- Push element x onto stack.pop() -- Removes the element on top of the stack.top() -- Get the top element.empty() -- ...
分类:
其他好文 时间:
2015-07-16 11:56:13
阅读次数:
105
LeetCode上面的一道题目,原文如下:
Implement the following operations of a queue using stacks.
push(x) -- Push element x to the back of queue.pop() -- Removes the element from in front of queue.peek() -- G...
分类:
其他好文 时间:
2015-07-14 11:23:27
阅读次数:
131
Implement the following operations of a queue using stacks.push(x) -- Push element x to the back of queue.pop() -- Removes the element from in front o...
分类:
其他好文 时间:
2015-07-12 17:06:51
阅读次数:
110
Implement Stack using QueuesImplement the following operations of a stack using queues.push(x) -- Push element x onto stack.pop() -- Removes the eleme...
分类:
其他好文 时间:
2015-07-12 12:43:16
阅读次数:
112
Implement the following operations of a queue using stacks.
push(x) -- Push element x to the back of queue.pop() -- Removes the element from in front of queue.peek() -- Get the front element.empty(...
分类:
其他好文 时间:
2015-07-11 16:48:45
阅读次数:
86
Implement the following operations of a queue using stacks.push(x) -- Push element x to the back of queue.pop() -- Removes the element from in front o...
分类:
其他好文 时间:
2015-07-11 07:54:35
阅读次数:
116
Implement the following operations of a stack using queues.push(x) – Push element x onto stack.
pop() – Removes the element on top of the stack.
top() – Get the top element.
empty() – Return whether...
分类:
其他好文 时间:
2015-07-10 23:45:02
阅读次数:
146