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搜索关键字:count words and letters-计算用户输入一行文本中的单词数和每个字母出现次数    ( 20381个结果
hackerrank---Find a string
题目链接在字符串a中查找字符串b出现的次数...貌似不可以用a.count()附上代码:1 a = raw_input().strip()2 b = raw_input().strip()3 cnt = 0;4 for i in xrange(len(a)):5 cnt += 1 if a....
分类:其他好文   时间:2014-05-14 04:13:06    阅读次数:308
[LeetCode]Reverse Words in a String
题目:Given an input string, reverse the string word by word.For example,Given s = "the sky is blue",return "blue is sky the".Clarification:What constitu...
分类:其他好文   时间:2014-05-13 22:45:04    阅读次数:317
aix用户登录次数受限问题(3004-300 输入了无效的登录名或密码)
当登录AIX系统,用户名或密码不正确以至于多次登录,超过系统设定的次数,如何解锁: 1.用root用户登录系统 2.chuser unsuccessful_login_count=0 db2inst1 此时用户名db2inst1解锁成功,可正常登录 说明:db2inst1是被锁定的用户 参考链接:AIX用户登录次数受限设置...
分类:其他好文   时间:2014-05-13 06:20:21    阅读次数:269
hdu 3336 Count the string
Count the string Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 4239    Accepted Submission(s): 1977 Problem Description It is wel...
分类:其他好文   时间:2014-05-13 00:14:55    阅读次数:357
Leetcode | Substring with Concatenation of All Words
You are given a string, S, and a list of words, L, that are all of the same length. Find all starting indices of substring(s) in S that is a concatena...
分类:其他好文   时间:2014-05-12 22:27:04    阅读次数:265
mysql 得到重复的记录
select devicetoken from client_user group by devicetoken having count(devicetoken)>1
分类:数据库   时间:2014-05-12 02:16:42    阅读次数:273
ZOJ 1151 Word Reversal反转单词 (string字符串处理)
链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=151 For each list of words, output a line with each word reversed without changing the order of the words. This problem contains multi...
分类:其他好文   时间:2014-05-11 22:20:43    阅读次数:443
Hibernate查询方式---HQL方式
这一种我最常用,也是最喜欢用的,因为它写起来灵活直观,而且与所熟悉的SQL的语法差不太多。条件查询、分页查询、连接查询、嵌套查询,写起来与SQL语法基本一致,唯一不同的就是把表名换成了类或者对象。其它的,包括一些查询函数(count(),sum()等)、查询条件的设定等,全都跟SQL语法一样。###...
分类:系统相关   时间:2014-05-11 17:36:26    阅读次数:290
leetcode | Text Justification
Given an array of words and a length L, format the text such that each line has exactly L characters and is fully (left and right) justified.You shoul...
分类:其他好文   时间:2014-05-11 15:15:29    阅读次数:287
并查集(判断一个图有几个连通块)
import java.util.Scanner; // 并查集 判断一个图中有几个联通块 public class UnionFind { private int[] father;// private int count;// 分量数量 public UnionFind(int N){ count=N; father=new int[N]; for(int i=0;i<N...
分类:其他好文   时间:2014-05-11 03:03:44    阅读次数:308
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