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AsyncTask使用注意事项
AsyncTask是android自带的一个异步处理线程  它带了很多参数 都很方便使用 但是有一些注意事项 1: 官网说明: AsyncTasks should ideally be used for short operations (a few seconds at the most.) If you need to keep threads running f...
分类:其他好文   时间:2015-04-04 06:52:53    阅读次数:177
AsyncTask使用注意事项
AsyncTask是android自带的一个异步处理线程它带了很多参数都很方便使用但是有一些注意事项1:官网说明:AsyncTasks should ideally be used for short operations (a few seconds at the most.) If you ne...
分类:其他好文   时间:2015-04-03 20:49:05    阅读次数:139
zoj 1745 Are We There Yet?
Are We There Yet? Time Limit: 2 Seconds      Memory Limit: 65536 KB Laurie's little brother Joey has been playing Find the Cookie with her. However, after the 32,767th time, Laurie is tired of i...
分类:其他好文   时间:2015-03-31 14:49:29    阅读次数:177
Action(8):Error -27728:Step download timeout(120 seconds)has expired when downloading
Action(8):Error -27728:Step download timeout(120 seconds)has expired when downloading出现如下图所示对话框上的错误信息时解决方法是:在Vuser Generator中的Vuser--->Run-Time Setti....
分类:其他好文   时间:2015-03-30 12:48:30    阅读次数:169
Burn the Linked Camp(bellman 差分约束系统)
Burn the Linked CampTime Limit: 2 Seconds Memory Limit: 65536 KBIt is well known that, in the period of The Three Empires, Liu Bei, the emperor of ...
分类:其他好文   时间:2015-03-28 21:39:04    阅读次数:214
zoj 5303 Grouping 缩点求最长路
点击打开链接 Grouping Time Limit: 2 Seconds      Memory Limit: 65536 KB Suppose there are N people in ZJU, whose ages are unknown. We have some messages about them. The i-th message shows that th...
分类:其他好文   时间:2015-03-21 18:41:36    阅读次数:154
ZOJ 3792 Romantic Value 最小割+求割边的数量
点击打开链接 Romantic Value Time Limit: 2 Seconds      Memory Limit: 65536 KB Farmer John is a diligent man. He spent a lot of time building roads between his farms. From his point of view, eve...
分类:其他好文   时间:2015-03-21 14:04:52    阅读次数:140
zoj1649-Rescue (迷宫最短路径)【bfs 优先队列】
http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=649RescueTime Limit:2 Seconds Memory Limit:65536 KBAngel was caught by the MOLIGPY! He was ...
分类:其他好文   时间:2015-03-20 23:42:09    阅读次数:167
zoj1004-Anagrams by Stack 【栈 回溯】
http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=4Anagrams by StackTime Limit:2 Seconds Memory Limit:65536 KBHow can anagrams result from se...
分类:其他好文   时间:2015-03-17 02:02:27    阅读次数:248
为什么基于TCP的应用需要心跳包(TCP keep-alive原理分析)
TCP keep-alive的三个参数用man命令,可以查看linux的tcp的参数:man 7 tcp其中keep-alive相关的参数有三个: tcp_keepalive_intvl (integer; default: 75; since Linux 2.4) The number of seconds between TCP keep-alive pr...
分类:其他好文   时间:2015-03-16 19:19:08    阅读次数:144
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