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485. Max Consecutive Ones
Given a binary array, find the maximum number of consecutive 1s in this array. Example 1: Input: [1,1,0,1,1,1] Output: 3 Explanation: The first two di ...
分类:其他好文   时间:2020-07-02 23:22:50    阅读次数:99
217. Contains Duplicate
Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the arr ...
分类:其他好文   时间:2020-07-02 22:01:14    阅读次数:60
two-sum
可能进不了大厂,但是还是要努力。 目前刷题主要是解决题目,关于复杂度的考量,emmm,下次一定。先做最简单的。。。。 题目描述 给出一个整数数组,请在数组中找出两个加起来等于目标值的数, 你给出的函数twoSum 需要返回这两个数字的下标(index1,index2),需要满足 index1 小于i ...
分类:其他好文   时间:2020-07-01 20:51:21    阅读次数:71
0045. Jump Game II (H)
Jump Game II (H) 题目 Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array r ...
分类:其他好文   时间:2020-06-30 09:14:16    阅读次数:59
【LeetCode】链表
24. Swap Nodes in Pairs https://leetcode.com/problems/linked-list-cycle/ Given a linked list, swap every two adjacent nodes and return its head. You m ...
分类:其他好文   时间:2020-06-29 22:41:37    阅读次数:55
java two map left join
java two map left join - 国际版 Bing https://cn.bing.com/search?FORM=U227DF&PC=U227&q=java+two+map+left+join 两个不同的Java对象的“左连接”-代码日志 https://stackoverflow ...
分类:编程语言   时间:2020-06-29 20:07:22    阅读次数:56
C# NamedPipeServerStream NamedPipeClientStream
The piped stream are bidirectional communcation.Meanwhile they can read and write. Write the NamedPipeServerStream and NamedPipeClientStream in two di ...
分类:Windows程序   时间:2020-06-29 18:52:59    阅读次数:92
1. Two Sum
题目链接:two-num 思路一:两层for循环暴力求解,结果超时 1 def twoSum(nums,target):#使用二维数组 2 for i in range(len(nums)): 3 for j in np.arange(i+1,len(nums)): 4 if(nums[i] + n ...
分类:其他好文   时间:2020-06-29 17:11:10    阅读次数:41
输入两个整数,要求输出其中较大者。用函数来找到大数
#include <stdio.h>int main(){ int max(int x,int y); int a,b,c; printf("Please input two data:\n"); scanf("%d%d",&a,&b); c=max(a,b); printf("max is :%d ...
分类:其他好文   时间:2020-06-29 17:05:39    阅读次数:202
Codeforces Round #653 (Div. 3) B. Multiply by 2, divide by 6 (数学)
题意:有一个数$n$,每次操作可以使$n*=2$或$n/=6$(如果能被整除),求最少操作次数使得$n=1$,如果不满足,输出$-1$. 题解:我们只要看$n$的质因子即可,如果要满足条件,那么它的质因子只能含有$2$和$3$,并且$2$的次数不大于$3$的次数.直接去找$2$和$3$的次数即可.( ...
分类:其他好文   时间:2020-06-29 13:41:34    阅读次数:79
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