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LeetCode:Longest Substring Without Repeating Characters
Given a string, find the length of the longest substring without repeating characters. Examples: Given "abcabcbb", the answer is "abc", which the leng ...
分类:其他好文   时间:2018-02-13 15:36:58    阅读次数:153
3. Longest Substring Without Repeating Characters 最长的子串不重复字符
Given a string, find the length of the longest substring without repeating characters.Examples:Given "abcabcbb", the answer is "abc", which the length... ...
分类:其他好文   时间:2018-02-12 23:41:19    阅读次数:317
3. Longest Substring Without Repeating Characters
Given a string, find the length of the longest substring without repeating characters. Examples: Given "abcabcbb", the answer is "abc", which the leng ...
分类:其他好文   时间:2018-02-12 00:47:59    阅读次数:214
LeetCode 424. Longest Repeating Character Replacement
原题链接在这里:https://leetcode.com/problems/longest-repeating-character-replacement/description/ 题目: Given a string that consists of only uppercase English ...
分类:其他好文   时间:2018-02-04 11:08:28    阅读次数:149
HDU 4045 Machine scheduling (第二类斯特林数+DP)
A Baidu’s engineer needs to analyze and process large amount of data on machines every day. The machines are labeled from 1 to n. On each day, the eng ...
分类:系统相关   时间:2018-02-04 00:31:25    阅读次数:196
leetcode笔记—String
3. Longest Substring Without Repeating Characters (medium) 最长的无重复的子字符串 Given a string, find the length of the longest substring without repeating char ...
分类:其他好文   时间:2018-02-01 10:45:51    阅读次数:180
Spring框架最简单的定时任务调用
package org.jeecgframework.core.timer; import org.springframework.scheduling.annotation.Scheduled; import org.springframework.stereotype.Component; @C... ...
分类:编程语言   时间:2018-01-17 20:12:11    阅读次数:201
3. Longest Substring Without Repeating Characters
"欢迎fork and star:Nowcoder Repository github" 3. Longest Substring Without Repeating Characters 题目 解析 solution思路循序渐进,很值得思考! 对找到元素后更新位置处理,i取max(mp[s[j]] ...
分类:其他好文   时间:2018-01-14 13:03:42    阅读次数:93
Hello 2018 D
D. Too Easy Problems D. Too Easy Problems You are preparing for an exam on scheduling theory. The exam will last for exactly T milliseconds and will c ...
分类:其他好文   时间:2018-01-11 18:19:37    阅读次数:221
Quartz学习——Quartz大致介绍(一)
1. 介绍Quartz是OpenSymphony开源组织在Job scheduling领域又一个开源项目,是完全由java开发的一个开源的任务日程管理系统,“任务进度管理器”就是一个在预先确定(被纳入日程)的时间到达时,负责执行(或者通知)其他软件组件的系统。Quartz用一个小Java库发布文件( ...
分类:其他好文   时间:2018-01-09 16:58:13    阅读次数:209
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