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Codeforces Round #242 (Div. 2) B. Megacity
The administration of the Tomsk Region firmly believes that it's time to become a megacity (that is, get population of one million). Instead of improving the demographic situation, they decided to ach...
分类:其他好文   时间:2014-10-24 11:09:27    阅读次数:181
[SPOJ VLATTICE]Visible Lattice Points 数论 莫比乌斯反演
7001. Visible Lattice Points Problem code: VLATTICE Consider a N*N*N lattice. One corner is at (0,0,0) and the opposite one is at (N,N,N). How many lattice points are visible from co...
分类:其他好文   时间:2014-10-24 11:05:49    阅读次数:294
Maximum Product Subarray
Find the contiguous subarray within an array (containing at least one number) which has the largest product.For example, given the array[2,3,-2,4],the...
分类:其他好文   时间:2014-10-24 10:26:11    阅读次数:269
java spring一个类型split的方法
/** * Take a String which is a delimited list and convert it to a String array. * A single delimiter can consists of more than one charact...
分类:编程语言   时间:2014-10-24 06:52:05    阅读次数:349
编写代码:ATM的登陆界面(用户验证、主菜单的选择) 查询-- 存款-- 取款-- 退出
#include #include int main (void){ int password,one,two,money1=1000000,money2=999999,a=0;//a为取的金额 money1为人命币 money2 为美元 printf("请输入您的密码:\n"); scanf("....
分类:其他好文   时间:2014-10-24 01:39:39    阅读次数:161
HDU 5073 Galaxy(居然是暴力)
Problem Description Good news for us: to release the financial pressure, the government started selling galaxies and we can buy them from now on! The first one who bought a galaxy was Tianming Yun an...
分类:其他好文   时间:2014-10-23 22:51:27    阅读次数:228
POJ 1017 Packets(积累)
【题意简述】:这个是别人的博客,有清晰的题意描述,和解题思路,借助他的想法,可以很好的解决这个问题! 【分析】:贪心?模拟?见代码 //216K 16Ms #include using namespace std; int main() { int ans,a,b,c,d,e,f,Two,One;// 其中Two表示2*2的个数,同理One表示1*1的个数。 int u[4] = {0...
分类:其他好文   时间:2014-10-23 22:46:26    阅读次数:231
FASTSOCKET
FASTSOCKETIt looks like there are like 3 separate optimizations, but I think the most important one is the "enable_listen_spawn" feature. Here is how ...
分类:其他好文   时间:2014-10-23 22:19:50    阅读次数:256
hibernate之关于一对一单向,双向关联映射
【hibernate】之关于一对一单向,双向关联映射首先我们来看,Hibernate官方对于一对一单向关联的解释:基于外键关联的单向一对一关联和单向多对一关联几乎是一样的。唯一的不同就是单向一对一关联中的外键字段具有唯一性约束。ok,那我们也可以这样理解,一对一其实就是多对一关..
分类:Web程序   时间:2014-10-23 21:03:59    阅读次数:306
HTK孤立词识别简单流程
1.数据准备[command] HSLab one.wav[Rec ] 开始录音[Stop ] 录音结束[Mark ] 选择需要标注的区域[Labelas] 输入标注 回车确定[Save ] 保存孤立词标注3个部分:起始静音(sil) 词语音(one) 结束静音(sil)按照上述步骤,录制训...
分类:其他好文   时间:2014-10-23 20:40:57    阅读次数:441
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