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《Thinking in C++》读书笔记——Chapter 3: The C in C++ (2)
Chapter3: The C in C++ (2)Bitwise operators(1)The bitwise exclusive or, or xor (^) produces a one in the output bit if one or the other input bit is a...
分类:编程语言   时间:2014-07-22 23:11:16    阅读次数:618
Leetcode | Work Break
Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words.For e...
分类:其他好文   时间:2014-07-22 23:08:32    阅读次数:383
Single Number
Single NumberGiven an array of integers, every element appearstwiceexcept for one. Find that single one.Note:Your algorithm should have a linear runti...
分类:其他好文   时间:2014-07-22 23:07:14    阅读次数:337
listBox的用法
1.属性列表:SelectionMode组件中条目的选择类型:None-根本不允许任何选择;One-默认值,只选择单个选项;MultiSimple-简单的多项选择,单击一次鼠标就选中或取消选中列表中的一项;MultiExtended-扩展的多项选择,类似windows中的选择操作.SelectedI...
分类:其他好文   时间:2014-05-01 08:05:56    阅读次数:584
Timus 1446. Sorting Hat 分类问题
At the start of each school year, a very important event happens at Hogwarts. Each of the first-year wizards and witches is assigned to one of the four Hogwarts houses. The bravest children are put ...
分类:其他好文   时间:2014-04-29 13:38:20    阅读次数:459
VM启动报错Cannot open the disk,Failed to lock the file
在windows下运行VMware创建的虚拟机时出错,无法运行。 错误提示大概为: Failed to lock the file Cannot open the disk 'D:\Windows Server 2008 R2 x64.vmdk' or one of the snapshot disks it depends on. 解决方法:        把虚拟机文件夹里【.lck】...
分类:其他好文   时间:2014-04-29 13:28:21    阅读次数:366
Hdu 1042 N! (高精度数)
Problem Description Given an integer N(0 ≤ N ≤ 10000), your task is to calculate N!   Input One N in one line, process to the end of file.   Output For each N, output N! i...
分类:其他好文   时间:2014-04-28 10:36:41    阅读次数:341
避免nrpe端进程监控多个接口
为了避免目标端nrpe进程监控多个接口而造成的安全漏洞。有必要固定服务端的地址,对nrpe.cfg配置中,有下列一行介绍 #SERVER ADDRESS # Address that nrpe should bind to in case there are more than one interface # and you do not want nrpe to bind on all in...
分类:其他好文   时间:2014-04-27 22:36:17    阅读次数:454
hdu1211
RSA is one of the most powerful methods to encrypt data. The RSA algorithm is described as follow: > choose two large prime integer p, q > calculate n = p × q, calculate F(n) = (p - 1) × (q - 1) ...
分类:其他好文   时间:2014-04-27 21:37:59    阅读次数:315
java Annotation原理
Annotations are one of the fundamental language changes introduced in Java SE5. They provide information that you need to fully describe your program, but that cannot be expressed in Java. Thus, anno...
分类:编程语言   时间:2014-04-27 21:14:59    阅读次数:431
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