问题描述
Oh Jesus! The Minecraft Server of XadillaX's came across a bug!
There's one way to solve this bug in game. That is to get a bucket of water and a bucket of lava and mix them to obsidian. But ...
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其他好文 时间：
2014-05-10 10:13:22
阅读次数：
307
如何基于android4.4.2的源码和android-4.3.1_r1的驱动编译I9250的ROM
作者：雨水 2014-05-04 联系方式：dennis.hu.cd at gmail.com
说明：经过多番折腾，终于把自己编译的Android4.4.2的源代码成功地跑在我的三星Galaxy Nexus I9250手机上了。期间离不开一位外国朋友的帮助，也就是参考资料[1]的...
分类：
移动开发 时间：
2014-05-10 09:59:46
阅读次数：
483
John is going on a fishing trip. He has h hours available (1 <= h <= 16), and there are n lakes in the area (2 <= n <= 25) all reachable along a single, one-way road. John starts at lake 1, but he can finish at any lake he wants. He can only travel from on...
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其他好文 时间：
2014-05-07 08:48:52
阅读次数：
515
【题目】
原文：
1.3 Design an algorithm and write code to remove the duplicate characters in a string without using any additional buffer. NOTE: One or two additional variables are fine. An
extra copy of...
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其他好文 时间：
2014-05-07 08:48:12
阅读次数：
372
题目大意：
有一种猜数字的游戏，你有G次机会以及L点生命值，游戏首先给定一个范围1～N，你要来猜在此范围内的一个数字X。你的每次猜测都会告诉你是猜高了还是低了，每次猜测都要损失一次猜测机会（即G--），但如果你猜的值比X高了，那么同时还要损失一点生命值（L--）。
现在主办人面临一个问题：若给定的范围太大，就有很有可能导致参赛者用尽机会和生命值也猜不到这个X；而范围太小的话又降低了趣味性。所以，需要你来帮忙，根据给定的G和L来确定一个尽量大的范围，同时确保该范围内的所有数字都是一定可以被猜到的。...
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其他好文 时间：
2014-05-07 08:27:26
阅读次数：
387
The number of steps
Time Limit: 1000ms Memory limit: 65536K 有疑问？点这里^_^
题目描述
Mary stands in a strange maze, the maze looks like a triangle（the first layer have one room，the seco...
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其他好文 时间：
2014-05-07 06:15:59
阅读次数：
427
The gray code is a binary numeral system where two successive values differ in only one bit.
Given a non-negative integer n representing the total number of bits in the code, print the sequence of gr...
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其他好文 时间：
2014-05-07 06:10:17
阅读次数：
370
One evening Johnny found some funny looking beens in his grandfather's garden shed, and decided to plant one of them. Next morning, to his surprise he found an enormous beanstalk growing in his back y...
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其他好文 时间：
2014-05-07 05:17:42
阅读次数：
303
Description
Squares and rectangles fascinated the famous Dutch painter Piet Mondriaan. One night, after producing the drawings in his 'toilet series' (where he had to use his toilet paper to draw on,...
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其他好文 时间：
2014-05-07 05:16:29
阅读次数：
385
AssertionError继承Error，提供了多个构造方法，代码如下：
/*
* Licensed to the Apache Software Foundation (ASF) under one or more
* contributor license agreements. See the NOTICE file distributed with
* this w...
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其他好文 时间：
2014-05-07 03:20:22
阅读次数：
579
