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Letter Combinations of a Phone Number
Given a digit string, return all possible letter combinations that the number could represent.A mapping of digit to letters (just like on the telephon...
分类:其他好文   时间:2014-04-30 03:52:56    阅读次数:411
LeetCode1:Two Sum
题目: Given an array of integers, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the t...
分类:其他好文   时间:2014-04-30 03:20:07    阅读次数:502
Mine Number(搜索,暴力) ACM省赛第三届 G
Mine NumberTime Limit: 1000ms Memory limit: 65536K有疑问?点这里^_^题目描述Every one once played the game called Mine Sweeping, here I change the rule. You are g...
分类:其他好文   时间:2014-04-30 01:05:41    阅读次数:857
LeetCode——Gray Code
The gray code is a binary numeral system where two successive values differ in only one bit.Given a non-negative integernrepresenting the total number...
分类:其他好文   时间:2014-04-30 00:21:32    阅读次数:536
POJ 1236
Network of SchoolsTime Limit:1000MSMemory Limit:10000KTotal Submissions:10500Accepted:4189DescriptionA number of schools are connected to a computer n...
分类:其他好文   时间:2014-04-29 20:33:42    阅读次数:567
Oracle ——存储过程
1、带参数的存储过程CREATE OR REPLACE PROCEDURE sp_pro2 (spname VARCHAR2, newsal NUMBER) ISBEGIN UPDATE emp SET sal = newsal WHERE ename=spname;END;--参数VARCHAR2...
分类:数据库   时间:2014-04-29 19:45:33    阅读次数:610
Letter Combinations of a Phone Number
思路很简单,就是通过map对应,随后通过递归调用,这里遇到了个问题就是开始用string &re ,然后往里传re+c是不可以的,本来想省点内存,结果不行,所以只能值传递了,后来才知道string竟然还有push_back()和pop_back(),服了。 1 class Solution { 2 ...
分类:其他好文   时间:2014-04-29 19:31:07    阅读次数:524
Oracle——函数
CREATE FUNCTION annual_income(spNAme VARCHAR2) RETURN NUMBER IS yearSal number(7,2);BEGIN SELECT (sal+NVL(comm,0))*12 INTO yearSal FROM emp WHERE enam...
分类:数据库   时间:2014-04-29 18:08:00    阅读次数:497
PL/SQL——编程——变量定义
1、变量标量类型(scalar)复合类型(composite)参照类型(reference)lob(large object)--定义一个变长字符串v_ename VARCHAR2(10)--定义一个小数,范围-9999.99~9999.99v_sal NUMBER(6,2)--定义一个小数,并给初...
分类:数据库   时间:2014-04-29 17:14:28    阅读次数:582
《Cracking the Coding Interview》——第18章:难题——题目4
2014-04-29 01:05题目:数数从0到n总共有多少个数字‘2’?解法:数位动态规划,可以O(log10(n))时间内解决。代码: 1 // 18.4 Count the number of 2s from 0 to n. 2 #include 3 using namespace std;....
分类:其他好文   时间:2014-04-29 14:44:34    阅读次数:380
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