码迷,mamicode.com
首页 >  
搜索关键字:physically based    ( 2864个结果
App Service overview Azure
App Service overview Azure App Service is an HTTP-based service for hosting web applications, REST APIs, and mobile back ends. You can develop in your ...
分类:移动开发   时间:2021-03-17 15:03:35    阅读次数:0
Proj THUDBFuzz Paper Reading: A Review of Machine Learning Applications in Fuzzing
2 Overview of Fuzzing Generation-based fuzzer Peach, Sulley Evolutionary Fuzzers honggfuzz, AFL, libFuzzer Mutation-based fuzzers where to mutate what ...
分类:移动开发   时间:2021-03-10 13:37:53    阅读次数:0
Deep Unfolding Network for Image Super-Resolution 论文解读
Introduction 超分是一个在 low level CV 领域中经典的病态问题,比如增强图像视觉质量、改善其他 high level 视觉任务的表现。Zhang Kai 老师这篇文章在我看到的超分文章里面是比较惊艳我的一篇,首先他指出基于学习(learning-based)的方法表现出高效, ...
分类:Web程序   时间:2021-03-02 12:05:45    阅读次数:0
rmanbak.sh
#creation:2021-02-02#Define variabledate=`date +%Y%m%d`basedir=/data2/backup#Create cd $basedirmkdir rmanbak0_$date#delete expire document#find $based ...
分类:其他好文   时间:2021-02-09 11:53:37    阅读次数:0
U3D地形工具真实城市 CityGen3D v1.3
CityGen3D - Procedural Unity Scenes From Real World Map Data With CityGen3D you can have terrain, roads and buildings all generated for you based on r ...
分类:其他好文   时间:2021-02-02 11:15:24    阅读次数:0
漫谈软件系统测试——通信节点识别
? A software system is a system of intercommunicating components based on software forming part of a computer system. 软件系统是以构成计算机系统一部分的软件为基础的内部通信组件的系统 ...
分类:其他好文   时间:2021-02-01 12:56:47    阅读次数:0
062.Python前段框架Django视图CBV
目录 一 CBV与FBV 1.1 创建项目 1.2 使用CBV改写 1.3 使用装饰器装饰CBV 1.4 使用装饰器装饰FBV 回到顶部 一 CBV与FBV CBV:Class Based View FBV:Function Based View 之前写过的都是基于函数的view,就叫FBV。还可以 ...
分类:编程语言   时间:2021-01-26 12:20:41    阅读次数:0
KVM Internal: How a VM is Created?
KVM is an acronym of “Kernel based Virtual Machine”, and is a virtualization infrastructure for the Linux kernel that turns it into a hypervisor.It is ...
分类:其他好文   时间:2021-01-20 12:16:47    阅读次数:0
Codeforces Round #689 (Div. 2, based on Zed Code Competition)D. Divide and Summarize(分治+dfs)
D. Divide and Summarize 题意 给你n个数,q次询问,问你能否具有满足和为s的序列。 思路 再求其有多少种和时需要使用$mid = max + min >> 1$来寻找有多少种和。 然后dfs,但是需要判断一下左面或者右面全部相等情况,否则会爆栈 #include<bits/s ...
分类:其他好文   时间:2021-01-19 12:24:43    阅读次数:0
【Azure Developer】使用Postman获取Azure AD中注册应用程序的授权Token,及为Azure REST API设置Authorization
Azure Active Directory (Azure AD) is Microsoft’s cloud-based identity and access management service, which helps your employees sign in and access res ...
分类:Windows程序   时间:2021-01-15 12:02:00    阅读次数:0
2864条   上一页 1 2 3 4 5 ... 287 下一页
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!